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AveGali [126]
3 years ago
7

A 15kg block has a constant acceleration of 2.2m/s^2 down a 30 degree incline

Physics
2 answers:
blagie [28]3 years ago
6 0
Please find word document attached.
Download docx
Nimfa-mama [501]3 years ago
5 0
Use Newton's Second law of motion and plug in what you know:
15sin30-friction=15a
15 times 9.8 times 0.5-15 times 2.2 =Friction
So Friction = 73.5 -33, or 40.5 Newtons
Hope this helps!
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A block of mass m=1kg sliding along a rough horizontal surface is traveling at a speed v0=2m/s when it strikes a massless spring
topjm [15]

Here we can use the work energy theorem

W_f + W_s = K_f - K_i

here we know that

K_f = 0

as it come to rest finally

K_i = \frac{1}{2}mv_i^2

K_i = \frac{1}{2}\times 1\times 2^2

K_i = 2 J

now work done by friction force will be given as

W_f = - F_f \times d = -\mu mg d

W_f = - \mu(1)(9.8)(0.10) = - 0.98\mu

Work done by spring force is given as

W_s = \frac{1}{2}k(x_i^2 - x_f^2)

W_s = \frac{1}{2}(10)( 0 - 0.10^2)

W_s = -0.05 J

so now plug in all data above

- 0.05 - \mu(0.98) = 0 - 2

\mu = 1.99

so above is the friction coefficient


4 0
4 years ago
Which of the following is not true of a form?
Ludmilka [50]

Answer:

It can only display one record at a time

Explanation:

Form ;

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3.It may contain images in the background.

4.This can be sorted data regardless of its source of information.

Only option C is wrong.

Therefore the answer C is correct.

4 0
4 years ago
A calcium-40 ion has a positive charge that is double the charge of a proton, and a mass of 6.64 ✕ 10−26 kg. At a particular ins
Zina [86]

Answer:

Detailed solution is given below

4 0
4 years ago
I NEED THIS A.S.A.P I WILL GIVE BRAINLIEST PLEASE HELP!!
VLD [36.1K]

Explanation:

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8 0
3 years ago
Read 2 more answers
A typical adult human has a mass of about 70 kg.
Misha Larkins [42]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2 
<span>= 2.40 x 10-3 N

b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N 
FMFE 2.40 x 10-3N685 N= 0.0004%</span>
3 0
3 years ago
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