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Vladimir [108]
3 years ago
9

A sample of oxygen gas at a pressure of 0.656 atm and a temperature of 27.2 °C, occupies a volume of 10.7 liters. If the gas is

allowed to expand at constant temperature to a volume of 13.1 liters, the pressure of the gas sample will be ______ atm.
Fill in the blank.
Chemistry
1 answer:
sladkih [1.3K]3 years ago
3 0

Answer:

The correct answer is 0.536 atm.

Explanation:

The formula to use to solve the given question is,

P1V1 = P2V2

Based on the given information, the initial pressure (P1) of the oxygen gas is 0.656 atm, the initial volume (V1) is 10.7 L. The new volume (V2) given is 13.1 L, there is a need to find the new pressure of the gas (P2).

Now putting the values in the above equation we get,

0.656 atm * 10.7 L = P2 * 13.1 L

P2 = 0.656 atm*10.7 L/13.1 L

P2 = 0.536 atm

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Answer:

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Explanation:

The gold foil experiment was performed by Rutherford and his research group in 1911 (at the beginning of the 20th century). In this experiment, α particles were bombed to gold foils, and films were placed surround it to collect the particles.

It was observed that most of the particles passed through of the foil undeflected, and for that, Rutherford stated that the atom was a "huge empty". Some particles were deflected, because they're attracted to the electrons at the electrosphere, and a small number of particles were complete deflected to the origin because they chocked with the small positive nuclei.

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