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3 years ago

When a liquid becomes a gas, the process is called ?

Chemistry

2 answers:

Liula [17]3 years ago

8 0

Answer:

This kind of phase change--liquid to gas--is called evaporation or vaporization. Water vapor can in turn be cooled to form liquid water.

Explanation:

when the water gets to hot it turns into gas lets take boiling water if you put a top on it what happens water rises because the water evaporated

Maslowich3 years ago

7 0

Answer:

evaporation or distillation

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A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

$Molarity=\frac{moles}{\text{Volume of solution(L)}}$

Moles of glucose = $\frac{18.5 g}{180 g/mol}=0.1028 mol$

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = $\frac{0.1028 mol}{0.1 L}=1.028 mol/L$

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = $M_1=1.208 mol$

Volume of the solution taken = $V_1=30.0 mL$

Molarity of the solution after dilution = $M_2$

Volume of the solution after dilution= $V_2=0.500L = 500 mL$

$M_1V_1=M_2V_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}$

$M_2=0.07248 mol/L$

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

$0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}$

Moles of glucose = $0.07248 mol/L\times 0.1 L=0.007248 mol$

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

4 0

4 years ago

What is the ph of a solution of 0.400 m k2hpo4, potassium hydrogen phosphate?

dusya [7]

When we can get Pka for K2HPO4 =6.86 so we can determine the Ka :

when Pka = - ㏒ Ka

6.86 = -㏒ Ka

∴Ka = 1.38 x 10^-7

by using ICE table:

H2PO4- → H+ + HPO4
initial 0.4 m 0 0

change -X +X +X

Equ (0.4-X) X X

when Ka = [H+][HPO4] / [H2PO4-]

by substitution:

1.38 X 10^-7 = X^2 / (0.4-X) by solving for X

∴X = 2.3x 10^-4

∴[H+] = X = 2.3 x 10^-4

∴PH = -㏒[H+]

= -㏒ (2.3 x 10^-4)
∴PH = 3.6

3 0

3 years ago

Look at the Recording station detector on the upper left side of the Gizmo. What happens when the seismic waves hit the recordin

Ne4ueva [31]

Answer:

I don’t know what recording station you’re referring to but, When seismic waves reach the seismograph, a graphical record, or seismogram, is produced

Explanation:

4 0

3 years ago

If the only thing we are interested in studying is how the number of particles affects pressure, what variables do we have to be

andre [41]

I’m sorryvvvgccxxggcfg

6 0

4 years ago

A 2.50 L solution contains 5.00 g of NaOH, which has a molecular weight of 40.00

Fantom [35]

Answer:

0.313mol/L

Explanation:

$\frac{5.00}{40.00} \times 2.50 = 0.3125$

3 0

3 years ago