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zhenek [66]
4 years ago
10

The sprinter experiences ___________ from A to B to C.

Physics
1 answer:
r-ruslan [8.4K]4 years ago
5 0

The sprinter experiences muscle cramps and a stray dog on the track from A to B, followed immediately by acute nausea and a gaggle of news photographers from B to C.

If none of these selections appears on the list of choices, then perhaps we can do better if you'll permit us a glance at the picture that accompanies the question, even if you still don't let us see the choices.

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Cual es el periodo entre cresta y cresta,si una
svet-max [94.6K]

translation: What is the period between crest and crest, if a

wave travels 85ms, if distance

is 4.5m. And what is its frequency.

Lo siento, pero no puedo responder a tu pregunta.

(también la gente informará si lo hace en inglés mentalmente en un idioma diferente, así que ... tal vez traducir)

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3 years ago
What kind of medium does ocean waves have
Anika [276]
Ocean waves propagate through the medium called 'sea water'.
3 0
4 years ago
In comparing sunspots to other areas of the sun's surface one can say that sunspots are...?
taurus [48]

Answer:

D. Cooler

Explanation:

The Sun's surface has a temperature ranging from 6 000 Kelvin, thus it is very hot. The radioactive reaction in the core of the Sun is a nuclear fusion reaction. This reaction ensures continuous release of high energy from the surface of the Sun.

But during the reaction, some parts becomes cooler than other parts on its surface. Which is due to the release of high amount of energy into space. The Sun's spot can be found in the cooler part of the Sun.

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3 years ago
HELP ME!!!!!!!!!!!!! DUE IN 10 MINUTES HURRY!!!!!!!
alexandr1967 [171]

Answer:

3.4 or 3 11/23

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7 0
3 years ago
Read 2 more answers
The formula h = -16t squared + 64t squared gives the height, h, and time, t, of an object launched from the ground with a speed
padilas [110]

Answer:

<em>Details in the explanation</em>

Explanation:

<u>Vertical Launch</u>

When an object is thrown vertically in free air (no friction), it moves upwards at its maximum speed while the acceleration of gravity starts to brake it. At a given time and height, the object stops in mid-air and starts to fall back to the launching point until reaching it with the same speed it was launched.

We are given an expression for the height of an object in function of time t

h = -16t^2 + 64t

<em>Please note we have deleted the second 'squared' from the formula since it's incorrect and won't describe the motion of vertical launch.</em>

We now have to evaluate h for the following times, assuming h comes in feet

At t=1 sec

h = -16(1)^2 + 64(1)=64-16=48\ ft

The object is at a height of 48 feet

At t=2 sec

h = -16(2)^2 + 64(2)=128-64=64\ ft

The object is at a height of 64 feet. This is the maximum height the object will reach, as we'll see below

At t=3 sec

h = -16(3)^2 + 64(3)=192-144=48\ ft

The object is at a height of 48 feet. We can clearly see it's returning from the maximum height and is going down

At t=4 sec

h = -16(4)^2 + 64(4)=256-256=0\ ft

The object is at ground level and has returned to the launch point.

5 0
3 years ago
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