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sweet [91]
4 years ago
5

what is the maximum torque on a coil 5 cm x 12 cm, composed of 600 turns, when it is carrying a current of 10^-5 A in a uniform

field of .1 T
Physics
1 answer:
Eduardwww [97]4 years ago
8 0

Answer:

3.6×10⁻⁶  Nm

Explanation:

From the question,

The expression for maximum torque is given as

τ = BANI.................Equation 1

where τ = maximum torque, B = magnetic field, A = Area of the coil, N = number of turns, I = current carried by the coil.

Given: B = 0.1 T, A = (5×12) = 60 cm² = 0.006 m², N = 600 turns, I = 10⁻⁵ A.

Substitute these values into equation 1

τ = 0.1(0.006)(600)(10⁻⁵)

τ = 3.6×10⁻⁶  Nm

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When using higher magnification, you need more light. which parts of the microscope can be adjusted to provide more light, and h
valina [46]

Increased lamp voltage is achieved by turning the light intensity dial.

To enlarge the diameter of the hole and let more light through the slide, the iris diaphragm was modified.

Condenser: Position it higher and closer to the slide's bottom to better direct light to the centre of the slide.

<h3>How do you adjust the light level on a microscope?</h3>

Utilize the brightness adjustment knob to change the brightness. Turn the brightness control knob while looking through the eyepieces to make sure there is no glare in the field of view.

Use a daylight balancing filter if your compound microscope has a certain sort of illumination. It typically rests directly on top of the luminator or in a filter holder above the light. This filter is blue.

The daylight balancing filter will correct the colour temperature and produce a higher-quality image if your microscope is lighted by tungsten or halogen (and a better colour image). This blue filter is not necessary if your microscope is an LED.

To learn more about light level on a microscope, visit:

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8 0
2 years ago
Two steamrollers begin 115 mm apart and head toward each other, each at a constant speed of 1.10 m/sm/s . At the same instant, a
NeX [460]

Answer:

The distance of fly travel is 115.06 m.

Explanation:

Given that,

Distance = 115 mm

Speed = 1.10 m/s

Speed of fly = 2.20 m/s

We need to calculate the relative speed

Using formula of relative speed

v=v_{1}+v_{2}

Put the value into the formula

v=1.10+1.10

v=2.20\ m/s

We need to calculate the time for the two steamrollers to meet each other

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{115}{2.20}

t=52.3\ sec

We need to calculate the distance of fly travel

Using formula of distance

d=vt

Put the value into the formula

d=2.20\times52.3

d=115.06\ m

Hence, The distance of fly travel is 115.06 m.

3 0
3 years ago
The weight of the mass added to the hanger is equal to the extra force on the gas, but what area should we use to calculate the
kari74 [83]

Answer: according to the Avagadro's law, volume is directly propotional to no of moles: VXn

according to the Charles law, volume is directly propotional to  temperatue: VXT

according to the Boyle's law, volume is inversely propotional to P: VX1/P

when we combine them we get:

VXnT1/P

V=knT/P

k= R(universal gas constant)

V=RnT/P

PV=nRT  

8 0
3 years ago
What is the horse power of an electric motor which can do by 1250 joule of work in 5 seconds​
Ksju [112]
1250 J in 5 sec= 250 Joule(s) per second (1250/5 0

250 Joules per second = 250 Watts ( 1J/s = 1 Watt per definition)

250 Watts output = 250/0.65 efficiency = 384 Watts input

1 Horsepower = 732 Watts

Motors 1 Horsepower and under are made in certain step sizes like

3/4 , 1/2 , 1/3, 1/4, 1/16 1/20 of a Horsepower.

3/4 Horsepower is 549 Watts

1/2 Horsepower is 366 Watts

so you need to 3/4 horsepower motor to achieve 1250 J of work in 5 seconds.
5 0
2 years ago
The normal force acting on an object and the force of static friction do zero work on the object. However the reason that the wo
spin [16.1K]

Answer:

<em>The normal force is perpendicular to the displacement</em>

<em>The static friction force produces no displacement</em>

Explanation:

Work Done By Special Forces

The work is a physical magnitude that measures the dot product of the force applied to an object by the displacement it produces in it.

W=\vec F\ \vec r

It can be written in its scalar version as

W=F.d.cos\theta

Being F and d the magnitudes of the force and displacement, and \theta the angle between them

If the angle is zero, the work is at maximum, it the angle is 90°, the work is zero. If the angle is between 90° and 180°, the work is negative.

The normal force acts in the vertical direction when the object is being pushed horizontally. It means the angle between the force and the displacement is 90°, thus the work is

W=N.d.cos90^o=0

The work is zero because the force and the displacement are perpendicular

The static friction force exists only when the object is being applied a force of a magnitude not large enough to produce movement, i.e. the object is at rest. If the object is moved, the friction force is still present, but it's called dynamic friction force, usually smaller than the static.

Since in this case, there is no displacement, d=0, and the work is

W=F_r(0)cos180^o=0

3 0
4 years ago
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