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gulaghasi [49]
3 years ago
14

The energy transfer diagram represents the energy of a person diving into a pool.

Physics
2 answers:
NNADVOKAT [17]3 years ago
8 0

Answer:

A) 1000 J

Explanation:

HACTEHA [7]3 years ago
5 0
The correct answer is: 
<span>A) 1000 J

In fact, energy cannot be destroyed nor created: this means that the total energy of the person must remain constant.

The initial energy of the person is U=8000 J, in form of gravitational potential energy. When he jumps and dives into the pool, this energy is converted into kinetic energy (K, 7000 J) and partially into thermal energy, Et. The final energy of the person, sum of kinetic energy and thermal energy, must be equal to the initial energy:
</span>U=K+E_t
<span>from which we can find the thermal energy:
</span>E_t = U-K=8000 J - 7000 J = 1000 J<span>
</span>
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What minimum heat is needed to bring 250 g of water at 20 ∘C to the boiling point and completely boil it away? The specific heat
Amiraneli [1.4K]

Answer:633.8 KJ

Explanation:

Given

mass of water\left ( m\right )=250gm

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Final temperature \left ( T_f\right )=100^{\circ}C

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heat of vaporization\left ( L\right )=22.6\times 10^5 J/kg

Heat required for process\left ( Q\right )=heat to raise water temperature from 20 to 100 +Heat to vapourize water completely

Q=mc\left ( T_f-T_i\right )+mL

Q=0.25\times 4190\times \left ( 100-20\right )+0.25\times 22\times 10^5

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A 1.50 µF capacitor and a 3.50 µF capacitor are connected in series across a 2.50 V battery. How much charge (in µC) is stored o
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Explanation:

The given data is as follows.

      C_{1} = 1.50 \times 10^{-6} F

      C_{1} = 3.50 \times 10^{-6} F    

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Hence, calculate the equivalence capacitor as follows.

    \frac{1}{C} = \frac{1}{C_{1}} + \frac{1}{C_{2}}

    \frac{1}{C} = \frac{1}{1.50 \times 10^{-6} F} + \frac{1}{3.50 \times 10^{-6} F}

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              Q = CV

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Thus, we can conclude that 2.65 \mu C is the charge stored on each given capacitor.

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3 years ago
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Answer:

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