Answer:
D
Explanation:
D Is The Answer Fella, My Head Hurt Really Bad
Answer:
The bismuth sample.
Explanation:
The specific heat
of a substance (might not be a metal) is the amount of heat required for heating a unit mass of this substance by unit temperature (e.g.,
.) The formula for specific heat is:
,
where
is the amount of heat supplied.
is the mass of the sample.
is the increase in temperature.
In this question, the value of
(amount of heat supplied to the metal) and
(mass of the metal sample) are the same for all four metals. To find
(change in temperature,) rearrange the equation:
,
.
In other words, the change in temperature of the sample,
can be expressed as a fraction. Additionally, the specific heat of sample,
, is in the denominator of that fraction. Hence, the value of the fraction would be the largest for sample with the smallest specific heat.
Make sure that all the specific heat values are in the same unit. Find the one with the smallest specific heat: bismuth (
.) That sample would have the greatest increase in temperature. Since all six samples started at the same temperature, the bismuth sample would also have the highest final temperature.
Answer:
C
Explanation:
This is a correct answer i think soo
Answer:
Mg
Explanation:
The standard reduction potentials are
<u>E°/V
</u>
Au³⁺(aq ) + 3e⁻ ⟶ Au(s); 1.42
Hg²⁺(aq) + 2e⁻ ⟶ Hg(l); 0.85
Ag⁺(aq) + e⁻ ⟶ Ag(s); 0.80
Cu²⁺(aq) + 2e⁻ ⟶ Cu(s); 0.34
Mg2+(aq) + 2e- ⟶ Mg(s); -2.38
The more negative the standard reduction potential, the stronger the metal is as a reducing agent.
Mg is the only metal with a standard reduction potential lower than that of Cu, so
Only Mg will react spontaneously with Cu²⁺.
Answer: The correct option is The properties of a noble gas.
Explanation: There are 7 periods in the periodic table.
The last element of each period are Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), Radon (Rn) and Ununoctium (Uuo).
- The electronic configuration for Helium is
. For He, The outermost electrons are 2.
- The electronic configuration for all the other elements is
( where, n = 2, 3, 4, 5, 6 and 7 respectively). For all the other gases, the outermost electrons are 8.
All these elements have stable electronic configuration and are not reactive in nature. Hence, they are considered as noble gases.
Therefore, the last element of each period always have the properties of a noble gas.