Answer:
376966.991 Joules
Explanation:
Given that :
the height = 12 m
Let assume the tank have a thickness = dh
The radius of the tank by using the concept of similar triangle is :
The area of the tank = 
The area of the tank = 
The area of the tank = 
The volume of the tank is = area × thickness
= 
Weight of the element = 
where;
= density of water ; which is given as 10000 N/m³
So;
Weight of the element = 
Weight of the element = 
However; the work required to pump this water = weight × height rise
where the height rise = 12 - h
the work required to pump this water = (12 - h)
the work required to pump this water = 
We can determine the total workdone by integrating the work required to pump this water
SO;
Workdone = 
= 
= ![\mathbf{ 69.44 \pi[ \frac{12h^3}{3}- \frac{h^4}{4}]^{12}}_0} }](https://tex.z-dn.net/?f=%5Cmathbf%7B%2069.44%20%5Cpi%5B%20%5Cfrac%7B12h%5E3%7D%7B3%7D-%20%20%5Cfrac%7Bh%5E4%7D%7B4%7D%5D%5E%7B12%7D%7D_0%7D%20%7D)
= ![\mathbf{69.44 \pi [ \frac{12^4}{3}-\frac{12^4}{4}]}](https://tex.z-dn.net/?f=%5Cmathbf%7B69.44%20%5Cpi%20%5B%20%5Cfrac%7B12%5E4%7D%7B3%7D-%5Cfrac%7B12%5E4%7D%7B4%7D%5D%7D)
= ![\mathbf{69.44 \pi*12^4 [ \frac{4-3}{12}]}](https://tex.z-dn.net/?f=%5Cmathbf%7B69.44%20%5Cpi%2A12%5E4%20%5B%20%5Cfrac%7B4-3%7D%7B12%7D%5D%7D)
= 
= 376966.991 Joules
The correct answer would be 68°F because (20°C × 9/5) + 32 = 68°F.
Answer:
290
Explanation:
Average acceleration is the change in velocity over change in time.
First, find the velocity by taking the derivative of position.
v(t) = dx/dt
v(t) = 38t + 21t²
At t = 3 and t = 9:
v(3) = 303
v(9) = 2043
So the average acceleration is:
a = Δv / Δt
a = (2043 − 303) / (9 − 3)
a = 290
Use appropriate units.
1). Work = (force) x (distance)
Work = (3,000 newtons) x (35 meters) = 105,000 newton-meters = <em>105,000 joules</em>
2). Power = (work) / (time)
Power = (105,000 joules) / (90 seconds)
= 1,166-2/3 joules per second =<em> 1,166 and 2/3 watts</em> .
<em>Note:</em>
That's no ordinary man.
1,166 watts is the same as roughly 1.6 horsepower.
Not too many people can sustain 1 horsepower or more for 90 seconds.
