A scuba tank of fixed volume is originally at a pressure of 50.0 atm and a temperature of 390 K. When it is placed near a fire p
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<u>Answer:</u> The freezing point of solution is -0.974°C
<u>Explanation:</u>
- To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
where,
= osmotic pressure of the solution = 12.1 atm
i = Van't hoff factor = 1 (for non-electrolytes)
M = molarity of solute = ?
R = Gas constant =
T = temperature of the solution = 298 K
Putting values in above equation, we get:
This means that 0.495 moles of glucose is present in 1 L or 1000 mL of solution
- To calculate the mass of solution, we use the equation:
Density of solution = 1.034 g/mL
Volume of solution = 1000 mL
Putting values in above equation, we get:
- To calculate the number of moles, we use the equation:
Moles of glucose = 0.495 moles
Molar mass of glucose = 180.16 g/mol
Putting values in above equation, we get:
Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.
- The equation used to calculate depression in freezing point follows:
To calculate the depression in freezing point, we use the equation:
Or,
where,
Freezing point of pure solution = 0°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal freezing point elevation constant = 1.86°C/m
= Given mass of solute (glucose) = 89.18 g
= Molar mass of solute (glucose) = 180.16 g/mol
= Mass of solvent (water) = [1034 - 89.18] g = 944.82 g
Putting values in above equation, we get:
Hence, the freezing point of solution is -0.974°C
Answer:
HOFO = (0, 0, +1, -1)
Explanation:
The formal charge (FC) can be calculated using the following equation:
<u>Where:</u>
V: are the valence electrons
N: are the nonbonding electrons
B: are the bonding electrons
The arrange of the atoms in the oxyacid is:
H - O₁ - F - O₂
Hence, the formal charge (FC) on each of the atoms is:
H: FC = 1 - 0 - 1/2*(2) = 0
O₁: FC = 6 - 4 - 1/2*(4) = 0
F: FC = 7 - 4 - 1/2*(4) = +1
O₂: FC = 6 - 6 - 1/2*(2) = -1
We can see that the negative charge is in the oxygen instead of the most electronegative element, which is the F. This oxyacid is atypical.
I hope it helps you!