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andrew11 [14]
3 years ago
12

Fhd the missing lumb x + 6 = -3(x - 2) Submit

Chemistry
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

wala kang jowa sabi ko haha

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2.0 moles of a monatomic ideal gas undergoes an isobaric process in which the temperature changes from 260 k to 320 k. what is t
Alik [6]

The change in the internal energy of the gas is 1.5×10∧3 J.

The internal energy of an ideal gas is directly proportional to the temperature of the gas:

ΔE = 3/2 × n × R × ΔT

ΔT = 320 K - 260 K

ΔT = 60 K; change of the temperature

n = 2.0 mol: amount of a monatomic ideal gas

R = 8.1 J/mol×K;the ideal gas constant

ΔE = 3/2 × 2 mol × 8.1 J/mol×K × 60 K

ΔE = 1500 J

ΔE = 1.5×10∧3 J;  the internal energy of the gas

Isobaric process is a type of process in which the pressure of the system stays constant.

More about an isobaric process: brainly.com/question/28106078

#SPJ4

4 0
1 year ago
Can someone please help me
Pachacha [2.7K]
Help you with what ma’am
6 0
3 years ago
What is the molar mass of Al2(SO3)3
Sonja [21]
The molar mass is 294.1527 g/mol
7 0
3 years ago
Which row in the table shows how many electrons there could be in the outer shell of an atom of V? ​
Amanda [17]

Answer:

Explanation:

The element V forms acidic oxide so it must be non- metal because oxides of non metal forms acidic oxide like sulphur ( s ) or chlorine ( Cl₂ )

sulphur forms SO₂ or SO₃ . Chlorine forms acidic oxide like Cl₂O₇ , Cl₂O₃ etc

These oxides are covalent compounds .

So V may have 6 or 7 electrons in the outermost orbit .

Hence option D is the right answer.

6 0
3 years ago
When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed? 2Al + 6HCl → 2AlCl
4vir4ik [10]

Well, we need to find the ratio of Al to the other reactant.


Al:HCl = 1:3


--> this means that for every 1 Al used, you have to use 3 HCl.



6*3 = 18 moles of HCl needed to fully react with 6 moles of Al. Since 13<18, HCL is the limiting reactant.



The ratio of HCl:AlCl = 3:1



13/3 = 4.3333...



The final answer is HCl is the limiting reactant with 4.3 moles of AlCl3 able to be produced.



Hope this helps!!! :)


6 0
3 years ago
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