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3 years ago

7

Which statement about dwarf planet locations is correct?

2 answers:

dexar [7]3 years ago

8 0

The second question is the correct one, as Cere's is in the asteroid belt, and Eris, Make-make, Haumea, and Pluto are in the Kuiper belt.

lesya692 [45]3 years ago

3 0

The answer is "Ceres is found in the asteroid belt and Eris, Makemake, Haumea, and Pluto are found in the Kuiper Belt."

There an as of now five formally grouped dwarf planets in our solar system. They are Ceres, Pluto, Haumea, Makemake and Eris. Ceres is situated inside the asteroid belt between the orbits of Mars and Jupiter, while the other smaller person planets are situated in the external nearby planetary group in, or close to, the Kuiper belt. Another six articles are in all likelihood predominate planets, yet are sitting tight for official grouping, and there might be upwards of 10,000 diminutive person planets in the solar system.

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The area in which the attraction and the repulsion of a magnet's poles are felt is a(n)

docker41 [41]

The are is called a magnetic field.

8 0

3 years ago

Read 2 more answers

A student measures the mass 8cm block of brown sugar to be 12.9g. what is the density of the brown sugar.

antoniya [11.8K]

Correction

A student measures the mass <em><u>8cm3</u></em> block of brown sugar to be 12.9g. what is the density of the brown sugar

Answer:

$1.6\ g/cm^{3}$

Explanation:

Density is defined as mass per unit volume of an object expressed as $\rho=\frac {m}{v}$ where $\rho$ is the density, m is the mass of sugar and v is the volume of the sugar. Considering that the volume is given as 8cm3 for sugar then we substitute this for v and mass of 12.9 g we substitute for g then the density will be

$\rho=\frac {12.9 g}{8 cm3}=1.6125\ g/cm^{3}\approx 1.6\ g/cm^{3}$

8 0

3 years ago

To win the game, a placekicker must kick a football from a point 44 m (48.1184 yd) from the goal, and the ball must clear the cr

Ganezh [65]

Answer:

The distance by the ball clear the crossbar is 1.15 m

Explanation:

Given that,

Distance = 44 m

Speed = 24 m/s

Angle = 31°

Height = 3.05 m

We need to calculate the horizontal velocity

Using formula of horizontal velocity

$u_{x}=u\cos\theta$

Put the value into the formula

$u_{x}=24\cos(31)$

$u_{x}=20.5\ m/s$

We need to calculate the vertical velocity

Using formula of vertical velocity

$u_{y}=u\sin\theta$

Put the value into the formula

$u_{y}=24\sin(31)$

$u_{y}=12.3\ m/s$

We need to calculate the time

Using formula of time

$t=\dfrac{d}{u_{x}}$

Put the value into the formula

$t=\dfrac{44}{20.5}$

$t=2.1\ sec$

We need to calculate the vertical height

Using equation of motion

$h=u_{y}t+\dfrac{1}{2}at^2$

Put the value into the formula

$h=12.3\times2.1-\dfrac{1}{2}\times9.8\times(2.1)^2$

$h=4.2\ m$

We need to calculate the distance by the ball clear the crossbar

Using formula for vertical distance

$d=h-3.05$

Put the value of h

$d=4.2-3.05$

$d=1.15\ m$

Hence, The distance by the ball clear the crossbar is 1.15 m

7 0

3 years ago

A 4810 kg demolition ball swings at the end of a 12.3 m cable on the arc of a vertical circle. At the lowest point of the swing,

faust18 [17]

The tension in the cable supporting the swing of the ball in the given vertical circle is 47,577.4 N.

<h3>Tension in the cable</h3>

The tension in the cable supporting the swing of the ball is calculated as follows;

T = mg + mac

T = mg + m(v²)/r

T = (4810 x 9.8) + (4810 x 1.06²)/12.3

T = 47,577.4 N

Thus, the tension in the cable supporting the swing of the ball in the given vertical circle is 47,577.4 N.

Learn more about tension here: brainly.com/question/918617

#SPJ1

4 0

2 years ago

B all figures represents molecules

Volgvan

C. Figure 11 and figure 1v are both compounds

5 0

3 years ago