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Alla [95]
4 years ago
7

A student states that every phase transition must involve a change in energy of the molecules of the substance. Is the student c

orrect? Explain your answer.
Chemistry
1 answer:
alexira [117]4 years ago
8 0
The student states that every phase transition must involve a change in energy of the molecules of the substance. The student is correct. In any phase change, there is a change in energy, for instance, phase transition from solid to liquid. The energy of the molecules in the solid is less than the energy in the liquid, this is because the molecules of the solid are compact while in the liquid, it moves freely. The energy increases as the molecules' speed increases. Similarly, the phase transition from liquid to gas experiences the same phenomenon. 
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35 Which element reacts with oxygen to form ionic bonds?(1) calcium (3) chlorine
QveST [7]

Covalent bonds exist between two nonmetal elements while ionic bonds exist between a metal and a nonmetal element. In this case, oxygen is a nonmetal and in order to create an ionic bond, the other substance should be a metal. The answer therefore to this problem is calcium. 
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Which statement best describes the relationship between kinetic energy, mechanical energy, and potential energy?
Luba_88 [7]

Answer:

C

Explanation:

because kinetic and potential are both parts of mechanical energy

you should know we learned it in class

5 0
2 years ago
Determine the pH of (a) a 0.40 M CH3CO2H solution, (b) a solution that is 0.40 M CH3CO2H and 0.20 M NaCH3CO2
elena-s [515]

Answer:

a) pH = 2.573

b) pH = 4.347

Explanation:

a) weak acid: CH3COOH

  • CH3COOH + H2O ↔ CH3COO- + H3O+

∴ Ka = 1.8 E-5 = [H3O+][CH3COO-] / [CH3COOH]

∴ <em>C</em> CH3COOH = 0.40 M

mass balance:

⇒ 0.40 M = [CH3COO-] + [CH3COOH].........(1)

charge balance:

⇒ [H3O+] = [CH3COO-].........(2)

(2) in (1):

⇒ [CH3COOH] = 0.40 - [H3O+]

replacing in Ka:

⇒ Ka = 1.8 E-5 = [H3O+]² / ( 0.40 - [H3O+] )

⇒ [H3O+]² = 7.2 E-6 - 1.8 E-5[H3O+]

⇒ [H3O+]² + 1.8 E-5[H3O+] - 7.2 E-6 = 0

⇒ [H3O+] = 2.6743 E-3 M

∴ pH = - Log [H3O+]

⇒ pH = 2.573

b) balanced reations:

  • CH3COONa + H2O → Na+  +  CH3COO-
  • CH3COOH + H2O ↔ CH3COO-  +  H3O+

∴ <em>C</em> CH3COOH = 0.40 M

∴ <em>C</em> CH3COONa = 0.20 M

mass balanced:

⇒ <em>C</em> CH3COOH + <em>C</em> CH3COONa = [CH3COO-] + [CH3COOH]

⇒ 0.60 = [CH3COO-] + [CH3COOH]......(1)

charge balanced:

⇒ [H3O+] + [Na+] = [CH3COO-]

∴ [Na+] = 0.20 M

⇒ [H3O+] + 0.20 M = [CH3COO-]........(2)

(2) in (1):

⇒ 0.60 M = ( [H3O+] + 0.20 ) + [CH3COOH]

⇒ [CH3COOH] = 0.40 - [H3O+]

replacing in Ka:

⇒ 1.8 E-5 = ([H3O+])([H3O+] + 0.20) / (0.40 - [H3O+])

⇒ 7.2 E-6  - 1.8 E-5[H3O+] = [H3O+]² + 0.20[H3O+]

⇒ [H3O+]² + 0.20[H3O+] - 7.2 E-6 = 0

⇒ [H3O+] = 4.499 E-5 M

⇒ pH = 4.347

7 0
4 years ago
Periodic Table Question
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Bottom left <span>on the periodic table</span>
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