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AVprozaik [17]
3 years ago
6

Hey man forgets that he said his coffee cup on the top of his car he starts to drive in the coffee cup rolls off the car onto th

e road how does the scenario demonstrate the first law of motion
Chemistry
1 answer:
Lyrx [107]3 years ago
8 0
It would move due to it not being<span> the same speed and in the same direction so it is acted upon by an unbalanced force.</span>
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Soft of easy help plz<br><br><br><br> B<br><br> C<br><br> A<br><br> D
umka21 [38]

Answer:

C

Explanation:

8 0
3 years ago
Which one of the following species is diamagnetic: a. F b. Zn2+ C. Cu2+ d. Ca+​
diamong [38]

Answer:

The correct answer to this question is C

Explanation:

3 0
3 years ago
A solution contains one or more of the following ions: Ag , Ca2 , and Co2 . Lithium bromide is added to the solution and no prec
koban [17]

Answer:

Ca^{2+}  and  Co^{2+}

Explanation:

Given:

A solution contains one or more of the following ions such as Ag, Ca_2 and Co_2

Here the Lithium bromide is added to the solution and no precipitate forms

Solution:

Since with LiBr no precipitation takes place therefore Ag+ is absent

Here on adding Li_2SO_4 to it precipitation takes place.

Precipitate is as follows,

Ca^{2+}(aq)+SO_4^2^-(aq)----->CASO_4(s)

Thus,

Ca^2^+ is present

When Li_3PO_4 is added again precipitation takes place.

Therefore the reaction is as follows,

Co^2^+(aq)+PO_4^3^-(aq)------>Co_3(PO_4)_2(s)

Therefore,

Ca^{2+}  and  Co^{2+} are present in the solution

3 0
3 years ago
When a quantity of electricity is converted to heat, what is the heat energy produced measured in
Mnenie [13.5K]
 It is measured in joules
8 0
3 years ago
Read 2 more answers
Suppose the reaction between nitrogen and hydrogen was run according to the amounts presented in Part A, and the temperature and
andrew11 [14]

Explanation:

Assuming that moles of nitrogen present are 0.227 and moles of hydrogen are 0.681. And, initially there are 0.908 moles of gas particles.

This means that, for N_{2}(g) + 3H_{2}(g) \rightarrow 2NH_{3}

 moles of N_{2} + moles of H_{2} = 0.908 mol

Since, 2 moles of N_{2} = 2 \times 0.227 = 0.454 mol

As it is known that the ideal gas equation  is PV = nRT

And, as the temperature and volume were kept constant, so we can write

        \frac{P(_in)}{n_(in)} = \frac{P_(final)}{n_(final)}

          \frac{10.4}{0.908} = \frac{P_(final)}{0.454&#10;}

       P_(final) = 10.4 \times \frac{0.454}{0.908}

                            = 5.2 atm

Therefore, we can conclude that the expected pressure after the reaction was completed is 5.2 atm.

7 0
3 years ago
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