Answer: For Number #1)
The solution above is an acidic solution
Kw= {H+}*{OH^-}
[OH^-] =Kw/[H+]
OH^-= 1.0*10^14/ 1.0*10^-4
=1.0*10^4
It seems like I begin to forget whole organic Chemistry. Anyway, the answer is 2-methylheptane-3-yne.
To build a name for this molecule, you need to:
1. Determine where there is the lowest chain beginning with the double, triple bond, or there is other thing for other types of organic molecules.. In this case you have one triplet bond, and the lowest chain there is the one that is below the bond.
2. In this small chain you see one "forks": CH3 and another CH3 go from the one CH. Put number 1 where there are the most number of such compounds, in this case it doesn't matter because we have one CH3 in one way and one CH3 in the another.
3. Determine the largest chain which surely has the triple bond. Put the numbers from 2 to the final beginning with CH3 where you put number 1. Your largest chain consists of 7 particles CH3, CH2, and CH.
4. You see that you also have one unnamed particle, the one which is "the other way" when you are in the CH which is below the triple bond on the picture. Its name will be 2-methyl because it is connected with particle #2 and it consists only of one carbon. If there were 2, it would be ethyl, and so on.
5. Finally, let's write a full name: put 2-methyl first, "2-methyl." Then, write a full name for the chain of 7 carbons, which has to be heptane, if it had 5, you would name it pentane, ethane, and so on. So, we have "2-methylheptane." Finally, you see that you have a triple bond after the carbon #3. Put a dash and the number of this carbon. "2-methylheptane-3" you should have. Since it is alkyne (organic molecule with one triple bond), you have to write "yne" at the end.
the final name is "2-methylheptane-3-yne." You can answer the question "explain your naming process" by using the answer I provided. Hope it helps. Good luck!
Answer: the best option to answer the question is the second one (letter B).
Explanation:
The question requires us to choose, among the options given, which one best corresponds to the correct form of disposal fo high-level nuclear waste.
High-level nuclear waste corresponds mainly to highly radioactive materials produced as byproducts of reactions that occur inside nuclear reactors. When they are not of use anymore, they are disposed in underground repositories, without any recycling. The place of disposal of this type of nuclear waste is usually placed in cannister which are placed underground and sealed with rocks. Since the time of decay of high-level nuclear waste can reach hundreds of thousands of years, this type of waste must be disposed of in a way that provides adequate protection for a long time.
Considering the information above, we can say that the best option to answer the question is the second one (letter B).
Answer:
Carbon
Explanation:
Carbon is a special element that can form covalent compounds at any shape.
Fuels all consists of carbon.
If you study organic chemistry you will learn more about the miracles of carbon.
Answer:
C3H8 + 3O2 -------------> 3CO2 + 4H2 (<em>Balanced</em><em> </em><em>Rea</em><em>ction</em><em>)</em>