All categories

3 years ago

What temperature in Celsius is 281 K

Chemistry

2 answers:

Ivan3 years ago

5 0

Answer: 7.85C

Explanation:

281K=7.85C

Nana76 [90]3 years ago

4 0

Answer:

7.85 C

Explanation:

you you can just Google it because that's what I did

You might be interested in

What did J.J. Thomson discover about the atom that changed the atomic model previously used?

galina1969 [7]

J.J. Thomson hypothesized and discovered that the atom was not the smallest unit of matter but that instead there were much smaller units. He discovered "sub-atomic particles" which make up atoms. The sub-atomic particle that Thomson discovered was the electron. He discovered this through a process of experiments testing cathode rays.

7 0

3 years ago

what is the volume of the air in a balloon that occupies 0.730 L at 28.0 c if the temperature is lowered to 0.00 C

svetoff [14.1K]

Answer:

The volume of the air is 0.662 L

Explanation:

Charles's Law is a gas law that relates the volume and temperature of a certain amount of gas at constant pressure. This law says that for a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement they have. the gas molecules. This is represented by the quotient that exists between volume and temperature will always have the same value:

$\frac{V}{T}=k$

If you have a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment and several the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

$\frac{V1}{T1}=\frac{V2}{T2}$

In this case:

V1= 0.730 L
T1= 28 °C= 301 °K (0°C= 273°K)
V2= ?
T2= 0°C= 273 °K

Replacing:

$\frac{0.730 L}{301K}=\frac{V2}{273K}$

Solving:

$V2=273K*\frac{0.730L}{301K}$

V2=0.662 L

The volume of the air is 0.662 L

6 0

3 years ago

In a chemical reaction 88g of CO2 was produced at r.t.p. Calculate the volume of CO2 in dm??

Tems11 [23]

Explanation:

$RFM = 44 \: g \\ 44g \: contain \: 1 \: mole \\ 88g \: will \: contain \: ( \frac{88}{44} \times 1) \\ = 2 \: moles \\ at \: room \: temperature \\ 1 \: mole \: occupies \: 24 \: {dm}^{3} \\ 2 \: moles \: occupies \: (2 \times 24) \\ = 48 \: {dm}^{3}$

6 0

3 years ago

How many moles are there in 32.4 grams of Na

Natalija [7]

Divide that my the molar mass which is 23 so 1.4087 g

8 0

3 years ago

A monomer is added to the end of a polymer chain in a __________ reaction.

aalyn [17]

Dehydration reaction

6 0

3 years ago

Read 2 more answers