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galina1969 [7]
3 years ago
10

Which of the followong parts does not rotate during starter operation? A. Commutator segments B. Armature windings c. Field wind

ings D. Drive pinion
Engineering
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer: B

Explanation: unless newer models added wingding to code inside fused computer...wingdings on a window ...not a motor

You might be interested in
How much power is needed to operate a Carnot heat pump if the pump receives heat 10°C and delivers 50 kW of heat at 40°C? at A)
mariarad [96]

Answer:

Power needed to pump=4.79 KW.

Explanation:

Given that:T_{1}=283K,T_{2}=313K,Q_{H}=50KW

We know that coefficient of performance of heat pump

 COP=\dfrac{T_{H}}{T_{H}-T_{L}}

So COP=\dfrac{313}{313-283}

      COP=10.43

COP=\frac{Q_{H}}{W_{in}}

      10.43 =\frac{50}{W_{in}}

W_{in}=4.79 KW

So power needed to pump=4.79 KW.

3 0
3 years ago
As a general rule of thumb, the ratio of the rate of etch-product formation to the flow rate of etch gas should be greater than
g100num [7]

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

Explanation:

8 0
3 years ago
Germanium forms a substitutional solid solution with silicon. Compute the number of germanium atoms per cubic centimeter for a g
brilliants [131]

Answer:

The number of germanium atoms per cubic centimeter for this germanium-silicon alloy is 3.16 x 10²¹ atoms/cm³.

Explanation:

Concentration of Ge (C_{Ge}) = 15%

Concentration of Si (C_{Si}) = 85%

Density of Germanium (ρ_{Ge}) = 5.32 g/cm³

Density of Silicon (ρ_{Si}) = 2.33 g/cm³

Atomic mass of Ge (A_{Ge})= 72.64 g/mol

To calculate the number of Ge atoms per cubic centimeter for the alloy, we will use the formula:

No of Ge atoms/cm³=[Avogadro's Number*C_{Ge}]/([C_{Ge}*A_{Ge}/ρ_{Ge})+(C_{Si}*A_{Ge}/ρ_{Si})]

                              = (6.02x10²³ * 15%) / [(15% * 72.64/5.32)+(72.64*85%/2.33)]

                              = (9.03x10²²)/(2.048+26.499)

                              = (9.03x10²²)/(28.547)

No of Ge atoms/cm³ = 3.16 x 10²¹ atoms/cm³

3 0
3 years ago
What is the mechanical advantage of a pulley with 3 support ropes?
snow_tiger [21]

Answer:

The mechanical advantage is 3 to 1

Explanation:

A frictionless pulley with three support ropes carries equal tension on each of the ropes thus;

Tension in each pulley rope = T

Total tension in the 3 ropes = 3 × T = 3·T

Direction of the tension forces on each rope = Unidirectional

Total force provided by the 3 ropes = 3·T

Therefore, a force, T, applied at the end of the rope will result in a lifting force of 3·T

Hence, the mechanical advantage = 3·T to T which is presented as follows;

Mechanical \ advantage = \dfrac{3 \cdot T}{T}  = \dfrac{3}{1}

The mechanical advantage = 3 to 1.

5 0
3 years ago
You are working in a lab where RC circuits are used to delay the initiation of a process. One particular experiment involves an
Ymorist [56]

Answer:

t'_{1\2} = 6.6 sec

Explanation:

the half life of the given circuit is given by

t_{1\2} =\tau ln2

where [/tex]\tau = RC[/tex]

t_{1\2} = RCln2

Given t_{1\2} = 3 sec

resistance in the circuit is 40 ohm and to extend the half cycle we added new resister of 48 ohm. the net resitance is 40+48 = 88 ohms

now the new half life is

t'_{1\2} =R'Cln2

Divide equation 2 by 1

\frac{t'_{1\2}}{t_{1\2}} = \frac{R'Cln2}{RCln2} = \frac{R'}{R}

t'_{1\2} = t'_{1\2}\frac{R'}{R}

putting all value we get new half life

t'_{1\2} = 3 * \frac{88}{40}  = 6.6 sec

t'_{1\2} = 6.6 sec

7 0
3 years ago
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