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Tcecarenko [31]
3 years ago
9

What would you call the following chemical reaction, Zn(s) + H2O(g) – Zno (s) + H2(g)

Chemistry
1 answer:
egoroff_w [7]3 years ago
5 0

I'd say it's single replacement/displacement

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Consider the balanced equation. 2HCl + Mg MgCl2 + H2 If 40.0 g of HCl react with an excess of magnesium metal, what is the theor
Serga [27]

Answer:

Theoretical yield of hydrogen is 1.11 g

Explanation:

Balanced equation, Mg+2HCl\rightarrow MgCl_{2}+H_{2}

As Mg remain present in excess therefore HCl is the limiting reagent.

According to balanced equation, 2 moles of HCl produce 1 mol of H_{2}.

Molar mass of HCl = 36.46 g/mol

So, 40.0 g of HCl = \frac{40.0}{36.46}moles of HCl = 1.10 moles of HCl

Hence, theoretically, number of moles of H_{2} are produced from 1.10 moles of HCl = (\frac{1}{2}\times 1.10)moles=0.550moles

Molar mass of H_{2} = 2.016 g/mol

So, theoretical yield of H_{2} = (0.550\times 2.016)g=1.11g

7 0
4 years ago
Read 2 more answers
What<br>was the initial volume of the hydrogen in cm3?​
svetlana [45]

Answer:

255.51cm3

Explanation:

Data obtained from the question include:

V1 (initial volume) =?

T1 (initial temperature) = 50°C = 50 + 273 = 323K

T2 (final temperature) = - 5°C = - 5 + 237 = 268K

V2 (final volume) = 212cm3

Using the Charles' law equation V1/T1 = V2/T2, the initial volume of the gas can be obtained as follow:

V1/T1 = V2/T2

V1/323 = 212/268

Cross multiply to express in linear form

V1 x 268 = 323 x 212

Divide both side by 268

V1 = (323 x 212)/268

V1 = 255.51cm3

Therefore, the initial volume of the gas is 255.51cm3

5 0
3 years ago
Read 2 more answers
How to balance Kmno4 + H2 So4+ CH3CH2OH-&gt; K2So4+ mnso4 + CH3COOH + H2o by oxidation number method ​
dezoksy [38]

Answer:

Ethanol + Potassium Permanganate + Sulfuric Acid = Acetic Acid + Manganese(II) Sulfate + Water + Potassium Sulfate

Explanation:

5 0
3 years ago
Glacier National Park in Montana is approximately 4,100 ft above sea level with an atmospheric pressure of 681 torr. At what tem
lapo4ka [179]

Answer : The temperature of liquid is, 369.9 K

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of liquid at 373 K = 681 torr

P_2 = vapor pressure of liquid at normal boiling point = 760 torr

T_1 = temperature of liquid = ?

T_2 = normal boiling point of liquid = 373 K

\Delta H_{vap} = heat of vaporization = 40.7 kJ/mole = 40700 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{760torr}{681torr})=\frac{40700J/mole}{8.314J/K.mole}\times (\frac{1}{T_1}-\frac{1}{373K})

T_1=369.907K\approx 369.9K

Hence, the temperature of liquid is, 369.9 K

6 0
3 years ago
Read 2 more answers
That's just the tip of the iceberg" is a popular expression you may have heard. It means that what you can see is only a small p
puteri [66]
Answer:

B 1.23 g/cc

Explanation:
For something to float on seawater, the density must be less than 1.03 g/mL. If the object sinks, the density is greater than 1.03 g/mL.

Let’s examine the answer choices. Keep in mind, the ice berg is mostly below the water level.

A. 0.88 g/cc
This is less than 1.03 g/cc, which would result in floating.

B. 1.23 g/cc
This is the best answer choice. The iceberg is mostly beneath the water, but some of it is exposed. The density is greater than 1.03 g/mL, but not so much greater that it would immediately sink.

C. 0.23 g/cc
This is less than 1.03 g/cc, which would produce floating.

D. 4.14 g/cc
This is much greater than 1.03 g/cc and the result would be sinking.
5 0
3 years ago
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