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Tcecarenko [31]
3 years ago
9

What would you call the following chemical reaction, Zn(s) + H2O(g) – Zno (s) + H2(g)

Chemistry
1 answer:
egoroff_w [7]3 years ago
5 0

I'd say it's single replacement/displacement

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Which bond will each pair of elements form?
jok3333 [9.3K]

Explanation: Sodium is a metal with a low electronegativity it will form an ionic bond with a non metal with a high electronegativity.

Both Florine and Sulfur are non metals with high electronegativity.

Neon is a noble gas family VIII A and normally doesn't form any bonds at all.

<u><em>MARK ME BRAINLIST</em></u>

7 0
3 years ago
suppose you are testing the buoyancy of different objects . study the table and choose object with the greatest buoyant force
Alika [10]
The formula to calculate buoyant force (FB) states that the upward force exerted on an immersed object is equal to the density (ρ ) of the fluid multiplied by both the fluid’s displaced volume (V) and the gravitational acceleration (g), or
FB = ρ x V x g.<span> 
I hope that helped with what you're doing. 
You can also try water displacement in a graduated cylinder.</span>
7 0
3 years ago
How do nervous and muscular work together
kirza4 [7]

Answer:

the nervous system tells the muscles what to do beause your nervous sytem is hooked up to your brain

Explanation:

4 0
2 years ago
A buffer is made with sodium acetate (CH3COONa) and acetic acid (CH3COOH); the Ka for acetic acid is 1.80×10−5. The pH of the bu
Goryan [66]

Answer:

B. 0.174

Explanation:

A buffer is formed by a weak acid (CH₃COOH) and its conjugate base (CH₃COO⁻, coming from sodium acetate). We can calculate the pH of this buffer using the Henderson-Hasselbalch equation.

pH = pKa + log [CH₃COO⁻]/[CH₃COOH]

pH - pKa = log [CH₃COO⁻]/[CH₃COOH]

3.98 - (-log 1.80 × 10⁻⁵) = log [CH₃COO⁻]/[CH₃COOH]

-0.760 = log [CH₃COO⁻]/[CH₃COOH]

[CH₃COO⁻]/[CH₃COOH] = anti log (-0.760)

[CH₃COO⁻]/[CH₃COOH] = 0.174

4 0
3 years ago
A 500. mL sample of oxygen is collected over 20.0∘C water at 760. torr. If the vapor pressure of water at 20∘C is 23.8 torr, wha
fomenos

Answer : The vapor pressure of the dry oxygen gas is, 736.2 torr

Explanation : Given,

Volume of sample of oxygen = 500 mL

Vapor pressure of oxygen + water = 760 torr

Vapor pressure of water = 23.8 torr

Now we have to determine the vapor pressure of the dry oxygen gas.

Vapor pressure of the dry oxygen gas = Vapor pressure of (oxygen + water) - Vapor pressure of water

Vapor pressure of the dry oxygen gas = 760 torr - 23.8 torr

Vapor pressure of the dry oxygen gas = 736.2 torr

Thus, the vapor pressure of the dry oxygen gas is, 736.2 torr

6 0
3 years ago
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