During a vacation trip, Taylor drives a car at one speed for
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Answer:
F = 3.84*10^-34N ^j
Explanation:
In order to calculate the magnetic force on the electron you use the following formula:
(1)
q: charge of the electron = -1.6*10^-19C
B: magnitude of the magnetic field = 0.80T
v: speed of the charge = 3.0*10^5 m/s
The direction of the motion of the electron is in the +i^ direction (+x direction). The magnetic field is in the +^k direction (+z direction).
The cross product between these unit vectors, by taking into account the minus sign of the charge, is given by:
-^i X ^k = ^j
The magnetic force is in the ^j direction (+y direction).
The magnitude of the magnetic force is:
The magnetic force on the electron has a magnitude of 3.84*10^-34N in the +y direction
