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barxatty [35]
3 years ago
6

Head restraints

Physics
2 answers:
meriva3 years ago
7 0

A - protect against whiplash injuries.

KengaRu [80]3 years ago
6 0
Most likely answer would be A
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For a projectile launched from the vertically from the surface the earth with initial velocity v0, the velocity of the projectil
UNO [17]

Answer:

(dr/dt) = √(v₀² + k²/r - k²/R)

Explanation:

v² = v₀² + k²[(1/r) - (1/R)]

v = velocity of Body launched from the surface of the earth

v = initial velocity of body

k = a constant

r = distance from the centre of the earth

R = radius of the earth

v² = v₀² + k²/r - k²/R

v = √(v₀² + k²/r - k²/R)

But v = dr/dt

(dr/dt) = √(v₀² + k²/r - k²/R)

(dr/√(v₀² + k²/r - k²/R)) = dt

To go one step beyond and integrate the differential equation

∫ (dr/√(v₀² + k²/r - k²/R)) = ∫ dt

Integrating the left hand side from 0 to r and the right hand side from 0 to t

Note, v₀, k and R are all constants

(- 4r²/k²)[√(v₀² + k²/r - k²/R)] = t

√(v₀² + k²/r - k²/R) = (- k² t/4r²)

(v₀² + k²/r - k²/R) = (- k² t/4r²)²

(v₀² + k²/r - k²/R) = (k⁴t²/16r⁴)

(k⁴t²/16r⁴) + (k²/r) = [v₀² - (k²/R)]

k² [(k²t²/16r⁴) + (1/r)] = [v₀² - (k²/R)]

[(k²t²/16r⁴) + (1/r)] = [(v₀²/k²) - (1/R)]

3 0
3 years ago
A wave with a short wave length will also have...?
Masja [62]
It'll have a higher frequency.

The product of (wavelength) times (frequency) for a wave
is always the same number ... it's the wave speed. 
So if one of them is small, the other one has to be big.
3 0
3 years ago
Which of the following has the greatest magnitude?
Anna11 [10]

The force of 30 Newtons has.  Its magnitude is 30 Newtons.

3 0
3 years ago
Ben Rushin is waiting at a stop light. Turns green, ben accelerated from rest at a rate of 6.00 m/s squared for a time of 4.10 s
Lera25 [3.4K]
D= vt +.5at^2
since he started at rest, v (initial velocity) is 0
so d=.5at^2
d = .5 (6m/s^2) (4.1s)^2 
then put that into a calculator.

4 0
3 years ago
A dog runs 30 feet to the north then 5 feet to the south what is the displacement of the dog
Nuetrik [128]
To look for displacement, just draw a vector from your beginning stage to your last position and settle for the length of this line. So we begin by drawing a line to the north which is 30 ft, since it is north, the line is going up, then it move 5 ft to the south, so put a line going down, so we are in 25 ft, North so that would be the answer.
5 0
3 years ago
Read 2 more answers
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