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3 years ago

Convert 1 second in to solar day

1 answer:

jeka943 years ago

8 0

1 Days to Seconds = 86400 70 Days to Seconds = 6048000
2 Days to Seconds = 172800 80 Days to Seconds = 6912000
3 Days to Seconds = 259200 90 Days to Seconds = 7776000
4 Days to Seconds = 345600 100 Days to Seconds = 8640000

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I litterly can not find this

choli [55]

Answer:

DNA Fingerprinting is all I could find

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3 years ago

At 900.0 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2SO2(g)+O2(g)→2SO3(g) At equilibrium, the partial

elena55 [62]

Answer : The partial pressure of $SO_3$ is, 67.009 atm

Solution : Given,

Partial pressure of $SO_2$ at equilibrium = 30.6 atm

Partial pressure of $O_2$ at equilibrium = 13.9 atm

Equilibrium constant = $K_p=0.345$

The given balanced equilibrium reaction is,

$2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)$

The expression of $K_p$ will be,

$K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times (p_{O_2})}$

Now put all the values of partial pressure, we get

$0.345=\frac{(p_{SO_3})^2}{(30.6)^2\times (13.9)}$

$p_{SO_3}=67.009atm$

Therefore, the partial pressure of $SO_3$ is, 67.009 atm

6 0

3 years ago

Which of the following statements is true regarding the nature of light?

Tanya [424]

I think the correct answer from the choices listed above is the last option. Straight line motion is both a wave and particle property of light. Light behaves both as a particle and as a wave. Hope this answers the question. Have a nice day.

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3 years ago

Advantages of solid expansion

bulgar [2K]

Answer:

One of the most useful use of expansion by heat is for swiches onmany tyes of machinery and home appliancesThemostats in the millions of cars are poerated by using the eaxpansion of metal Themometers arre another example,

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3 years ago

A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplit

likoan [24]

Answer:

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Explanation:

We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg

Length of wire l = 84 cm = 0.84 m

So mass density $\mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m$