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mezya [45]
3 years ago
6

Find the equation of a line that passes through the points (-1,5) and (3,-3). Write the equation in slope-intercept, point-slope

, and standard form.
Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0
\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{5})\qquad 
(\stackrel{x_2}{3}~,~\stackrel{y_2}{-3})
\\\\\\
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-3-5}{3-(-1)}\implies \cfrac{-3-5}{3+1}\implies -2
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-5=-2[x-(-1)]
\\\\\\
\boxed{y-5=-2(x+1)}\implies y-5=-2x-2\implies \boxed{\stackrel{slope-intercept~form}{y=-2x+3}}
\\\\\\
\boxed{\stackrel{standard~form}{2x+y=3}}
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