Answer:
The initial speed of 2 kg cart is 0.4 m/s.
Explanation:
Given that,
Mass of the cart 1,
Mass of cart 2,
Initial speed of car 2, (it is at rest)
After the collision,
Speed of cart 2, (right direction)
Speed of cart 1, (right)
We need to find the initial speed of 2 kg cart. It is a case of conservation of linear momentum. It is given by :
is the initial speed of 2 kg cart.
So, the initial speed of 2 kg cart is 0.4 m/s. Hence, this is the required solution.
A circle has a revolution of 360°. Since there are 12 hour markings, each hour interval has an angle of 30°. In radians, that would be equal to π/6 radians. So, in every 1 hour that passes, it covers π/6 of an angle. So, the angular velocity denoted as ω is π/6 ÷ 1 hour = π/6 rad/h. We can compute the average linear velocity, v, from the relationship:
v = rω, where r is the radius of the circle which is the length of the hour hand
v = (2.4 cm)(π/6 rad/h)
v = 1.257 cm/hour
Therefore, the average velocity is 1.257 cm per hour.
For the average acceleration, it is equal to zero. The hands of the clock move at a constant velocity. Since acceleration is the change of velocity per unit time, there is no change of velocity because it's constant. That's why it is zero.
Answer:
You'd have to show the picture..
Period = 2 seconds.
frequency = 1/2 cycle/second = 1/2 Hz
If it falls twice every four seconds, then it falls once every two seconds, therefore one falling period is two seconds.
Hz is equal to cycles per second. So if it goes through one cycle per two seconds, then it goes through 1/2 cycle per one second.
Hope this helps!
If you take 50 meters and divide by 23.1 seconds, you will get 2.16 meters per second.
So his average speed is 2.16 m/s.