The electrostatic potential energy, U, of one point charge q at position d in the presence of an electric field E is defined as the negative of the work W done by the electrostatic force to bring it from the reference position d to that position

Thus, to double the electric potential energy U we need to reduce the distance of separation by half (1/2) because they are inversely proportion
I say it helped then because TrueType had room
Answer:
The distance travelled on the freeway is 149.5 miles.
Explanation:
The school bus travels on the freeway at constant speed. According to the statement, we need to calculate the distance travelled by the vehicle by means of the following formula:
(1)
Where:
- Traveled distance, in miles.
- Speed, in miles per hour.
- Time, in hours.
If we know that
and
, then the distance travelled by the school bus is:



The distance travelled on the freeway is 149.5 miles.
Lift force exerted by the air on the rotors=143244 N
Explanation:
we use Newtons second law
F- (M+m)g=(M+m)a
F= lift force
m= mass of helicopter= 13000 Kg
M= mass of car= 2000 lb=907.2 kg
a= acceleration= 0.5 m/s²
g= acceleration due to gravity
F- (M+m)g=(M+m)a
F=(M+m)(a+g)
F=(13000+907.2)(0.5+9.8)
F=143244 N
Answer:
it would be 3
Explanation:
because you have to divide the length by the height of the incline.