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agasfer [191]
3 years ago
5

Can anybody helppp me with this

Physics
2 answers:
GREYUIT [131]3 years ago
8 0

Answer:

Iron Rusting

6th grade stuff or 5th i think

Explanation:

KonstantinChe [14]3 years ago
4 0

Answer:

Salt dissolving

Explanation:

Dis solving salt in water doesn't change it's chemical composition

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1. A 3.1 kg cart is traveling at 7.12 m/s to the right and it has a head on elastic collision with a 11.7 kg cart traveling at 1
Rashid [163]

Answer:

1.03 m/s

Explanation:

I'm too lazy to write the explanation down but my teacher graded this and it was right

6 0
3 years ago
In a pilot study to help train a group of data collectors who will evaluate childrens pain using a FACES rating scale, the resea
muminat

Answer:

Option c. Inter-rater Reliability

Explanation:

Here, the rating is done by a group of data collectors under training for evaluation children's pain on Faces scale which is a scale ranging from 0 to 10 with different expressions or faces with a happy face at 0 to a crying face at 10.

Also in Inter-rater Reliability, the relative consistency of a study or test is assessed and the extent to which different group members rated the same behavior, the consistency of which is evaluated.

Thus it can also be helpful in interviews, etc.

6 0
3 years ago
A boy jogs 250 meters in 110s what is the average speed
Artyom0805 [142]
The rule to get the average speed is as follows:
average speed = average distance / average time

We are given that:
distance = 250 m
time = 110 sec

Substitute with the givens in the above equation to get the average speed as follows:
average speed = 250/110 = 25/11 meters/sec
3 0
3 years ago
A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 5.64 10-2 kg/s. the density of the gasoline is 735
Irina18 [472]
Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
Density of gasoline, D = 735 kg/m³
Radius of fuel line, r = 3.43 x 10⁻³ m

Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²

Let v =  speed of pumping the gasoline, m/s
Then the mass flow rate is 
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s

The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
0.027166v = 0.0564
v = 2.076 m/s

Answer:  2.076 m/s
The gasoline moves through the fuel line at 2.076 m/s.
7 0
3 years ago
Read 2 more answers
You add 500 mL of water at 10°C to 100 mL of water at 70°C. What is the
Sphinxa [80]

Answer:

Option (c) : 20°C

Explanation:

t(final) =  \frac{w1 \times t1 + w2 \times t2}{w1 + w2}

T(final) = 500* 10 + 100*70/600 = 20°C

4 0
3 years ago
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