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3 years ago

14

The runner reaches the first camera, at the 500 m mark, at 9:03:05 a.m. and the second camera, at the 600 m mark, at 9:03:25 a.m

. What is her average speed over that time interval

1 answer:

SVEN [57.7K]3 years ago

7 0

Answer:

Explanation:

Distance travelled = 600 - 500 = 100 m

Time taken = 9:03:25 a.m.- 9:03 :05 a.m.

= 20 s

average speed = distance / time taken

= 100 / 20 m /s

= 5 m /s

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