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dexar [7]
3 years ago
10

There's a 50 gram sample of our Ra-229 it is half-life is 4 minutes how much will be left after 12 minutes

Chemistry
1 answer:
KIM [24]3 years ago
7 0

The half life of an isotope is the amount of time it will take for the given isotope to decay till the point where it reaches half of what amount you had started with.

If the half life of Ra-229 is 4 minutes then every 4 minutes the sample is reduced to half of what you had before

4 minutes.)     50/2 Ra-229 --> 25g Ra-229

8 minutes.)     25/2 Ra-229 --> 12.5 Ra-229

12 minutes.)    12.5/2 Ra-229 --> 6.25 Ra-229 remaining

<em>I beleive this is the correct answer</em>

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4.One rubber tire can generate about250,000 BTUS (1BTU=.0003KW ) when it is burned. The average American home consumes about 10,
jekas [21]

Answer:

The number of tires required to power ten homes for one year is approximately 2,730 tires

Explanation:

The given information are;

The energy generated by burning one rubber tire = 250,000 BTUs

1 BTU = 0.0003 kW

The amount of energy consumed by the average American home = 10,000 kWh

Therefore, the amount of energy generated by burning one tire in kW can be found as follows;

The energy generated by burning one rubber tire = 250,000 BTUs

1 BTU = 0.0003 kW

∴ 1 BTU × 250,000 = 250,000 BTUs = 0.0003 kW × 250,000 = 75 kW

We note that 250,000 BTUs is equivalent to 263764 kJ

1 kWh is equivalent to 3600 kJ

10,000 kWh = 10,000 × 3600 = 36,000,000 kJ

The energy requirement for ten homes  for one year = 10 × 36,000,000 kJ = 360,000,000 kJ

At 50% efficiency, the energy produced per tire = 0.5 × 263764 kJ = 131,882 kJ

The electrical energy produced per tire = 131,882 kJ/tire

The number of tires required to power ten homes for one year = 360,000,000 kJ/  131,882 kJ/tire = 2,729.71293  ≈2,730 tires

The number of tires required to power ten homes  ≈2,730 tires.

8 0
3 years ago
What is empirical evidence
vladimir2022 [97]
The correct answer is b
7 0
2 years ago
At the boiling point, the vapor pressure of a liquid is equal to the _______.
Marat540 [252]
At the boiling point, the vapor pressure of a liquid is equal to the atmospheric pressure.
6 0
3 years ago
What mass of aluminum is produced by the decomposition of 5.0 kg al2o3?
Nina [5.8K]
The  mass for  of aluminum that is produced  by  the decomposition  of  5.0 Kg Al2O3 is 2647 g or 2.647  Kg

          calculation
  Write  the equation for decomposition  of Al2O3

Al2O3 = 2Al  + 3 O2

find the  moles  of  Al2O3 =  mass/molar mass

convert  5 Kg  to g   = 5 x1000 = 5000 grams
molar mass of  Al2O3 =  27 x2 + 16 x3  = 102 g/mol

 moles =5000 g/  102 g/mol = 49.0196 moles

by use  of mole ratio between Al2O3 to  Al  which is 1:2  the moles of Al = 49.0196 x2 =98.0392  moles


mass of  Al = moles x molar  mass

= 98.0392 moles x  27g/mol = 2647  grams  or 2647/1000 = 2.647 Kg


7 0
3 years ago
Read 2 more answers
Exactly 10.7 mL of water at 28.0 °C is added to a hot iron skillet. All of the water is converted into steam at 100.0°C. The mas
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Answer:

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Explanation:

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Download pdf
3 0
3 years ago
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