Answer:
Na(sodium atom) = 6 atoms , P(phosphorus atom) = 2 atoms, Oxygen(Oxygen atom) = 8 atoms , Co(cobalt atom) = 2 atoms, Cl(chlorine atom) = 4 atoms
Explanation:
2Na3PO4(aq) + 2CoCl2(aq) → 2Co3(PO4)2(s) + 6NaCl(aq)
The question ask us to list the number of the kind of atom found on the left side(reactant) of the chemical equation. The question also reiterated that the order of the numbers should be the same as the order of the elements on the left side of the equation.
The type of atoms found on the left side of the equation are as follows;
Na(sodium atom) = 6 atoms
P(phosphorus atom) = 2 atoms
Oxygen(Oxygen atom) = 8 atoms
Co(cobalt atom) = 2 atoms
Cl(chlorine atom) = 4 atoms
The equation on the left hand side have sodium atom, phosphorus atom, oxygen atom, cobalt atom and chlorine atom.
Note: The given equation is not balanced but it can be balanced as follows;
2Na3PO4(aq) + 3CoCl2(aq) → Co3(PO4)2(s) + 6NaCl(aq)
The balanced equation have the following number of atom on the left side:
Na(sodium atom) = 6 atoms
P(phosphorus atom) = 2 atoms
Oxygen(Oxygen atom) = 8 atoms
Co(cobalt atom) = 3 atoms
Cl(chlorine atom) = 6 atoms
