<span>Molecules themselves</span>
The acceleration of gravity on Jupiter is listed as <em>24.79 m/s²</em> .
That's roughly 2.53 times its value on Earth. So if you weigh, let's say,
130 pounds on Earth, then you would weigh about 328 pounds on Jupiter.
Grav Force = GMm/r squared. M is earth's mass. m is the probe. r is distance to centre of earth.Given that 600 = GMm/(10,000^2).GMm = 600x(10,000^2) for 10, 000 milesGMm = ? x (20,000^2) for 20, 000 milestherefore600x(10,000^2)=? x (20,000^2)therefore [600x(10,000^2)]/(20,000^2)=? [600x(1x1)]/(2x2)=? [600/4]=? ?=150lb.Same procedure for b and c.Please ask if you want further help.
Answer:
Δx = 39.1 m
Explanation:
- Assuming that deceleration keeps constant during the braking process, we can use one of the kinematics equations, as follows:
where vf is the final velocity (0 in our case), v₀ is the initial velocity
(25 m/s), a is the acceleration (-8.0 m/s²), and Δx is the distance
traveled since the brakes are applied.
- Solving (1) for Δx, we have: