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3 years ago

Write this in km 2000m

Physics

2 answers:

Cloud [144]3 years ago

6 0

$2000m \to\boxed{2km}$

postnew [5]3 years ago

3 0

<em>we know that 1000m = 1 km
multiplying both sides by 2
2 </em>×<em>1000 m = 2</em>×<em>1 km
2000m = 2 km answer :)</em>

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iragen [17]

Answer:

v = 0.999981c m/s

Explanation:

Using the time dilation equation

$T = \frac{T_{0} }{\sqrt{1 - \frac{v^{2} }{c^{2} } } }$

T = stationary time = 100 years

T₀ = 11/12 years = 0.917 years

v = speed of travel in the space = ?

c = speed of light = 3 * 10⁸ m/s

$100 = \frac{0.917 }{\sqrt{1 - \frac{v^{2} }{(3*10^{8} )^{2} } } }\\$

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v = 299987395.57 m/s

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3 years ago

object x and y fall from a same height and object x is heavier than y which object would fall faster qnd y

hjlf

Answer: They’d fall at the same speed, because air resistance is the only thing that makes an object fall faster than another. There’s a video somewhere on the internet of a bowling ball and a feather falling at the same speed in a vacuum, if you look for it. Hope this helps!

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3 years ago

An unstrained horizontal spring has a length of 0.40 m and a spring constant of 340 N/m. Two small charged objects are attached

Hatshy [7]

Answer:

(a) Both the charges are positive or negative.

(b) Teh value of each charge is 1.53 x 10^-5 C.

Explanation:

Spring constant, K = 340 N/m

Natural length, L = 0.4 m

stretch, y = 0.033 m

(a) Let the charge on each sphere is q and they repel each other so the nature of charge of either sphere may be both positive or both negative.

(b) The electrostatic force is balanced by the spring force.

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3 years ago

What is the electrical force between q2 and q3? recall that k = 8.99 × 109 n•meters squared over coulombs squared.. 1.0 × 1011 n

max2010maxim [7]

The magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.

<h3>What is the magnitude of electrical forces between two charges?</h3>

The magnitude of the electrical force between two charges refers to the attractive or repulsive forces that exists between two charges separated by a given distance in an electric field.

The magnitude of the electrical force, F between the two charges q2 and q3 is given be my the formula below

$F = \frac{K \times q_2 \times q_3}{d^{2}}$

Therefore, the magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.

Learn more about electrical force at: brainly.com/question/17692887

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2 years ago

Calculate the frequency (v) in Hertz (Hz) of a wave that has a wavelength of 4.71 meters.

MissTica

Answer:

6.37 x 10⁷Hz

Explanation:

Given parameters:

Wavelength = 4.71m

Unknown:

Frequency = ?

Solution:

To solve this problem, we use the expression below:

V = F∧

V is the velocity = 3 x 10⁸m/s

F is the frequency

∧ is the wavelength

3 x 10⁸ = F x 4.71

F = 63694267.52Hz = 6.37 x 10⁷Hz

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3 years ago