Answer:
Time, t = 8 seconds
Explanation:
An object is thrown upward from the top of a 128-foot building with an initial velocity of 112 feet per second. The height h as a function of time t is given by :

We need to find the time when the object will hit the ground. When it will hit the ground, h = 0
So,

On solving the above quadratic equation, we get the value of t = 8 seconds. So, after 8 seconds the object will hit the ground. Hence, this is the required solution.
Average velocity is the change in distance divided by the time it takes to travel that distance. so the first one.
Answer:
Bnet=1.006*10^-6T
Explanation:
One long wire lies along an x axis and carries a current of 43 A in the positive x direction. A second long wire is perpendicular to the xy plane, passes through the point (0, 5.9 m, 0), and carries a current of 41 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0, 1.7 m, 0)?
the magnetic field Bnet=
the magnetic field due this long wire is given by
B1=∨I1/
..............................1
B2=∨I2/
............................2
Bnet=
.......................3
Bnet=v/2*pi
Bnet=4*pi*10^-7/(2
)
Bnet=0.0000002*(641.72)^.5
Bnet=1.006*10^-6T
Answer:
+14.0 m/s
Explanation:
we have mV + Mv = mU + Mu we solve for U = (mV + Mv - Mu)/m = (328*19.1 + 790*13 - 790*15.1)/328 = 14. Answer