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lorasvet [3.4K]
3 years ago
5

Beth moves a 15 N book 20 meters in 10 seconds. How much power was produced?

Physics
1 answer:
Mice21 [21]3 years ago
5 0

Answer:

30 Watts

Explanation:

 Power = Work/Time

Work = Force*Distance

Power = Force * Distance / Time

Power = 15 N * 20 meters / 10 sec

Power = 30 Watts

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Compare these two collisions of a PE student with a wall.
Stolb23 [73]

1) The variable that is different in the two cases is \Delta t, the duration of the collision

2) The change in momentum is the same in the two cases

3) The impulse is the same in the two cases

4) Case B will experience a greater force

Explanation:

1)

The variable that is different in the two cases is \Delta t, the duration of the collision.

In fact, in the first case the wall is padded: this means that the collision will be "softer" and therefore will last longer, so the duration of the collision, \Delta t, will be larger.

In the second case instead, the wall is unpadded: this means that the collision is "harder" and so it will last less time, therefore the duration of the collision \Delta t will be smaller.

2)

The change in momentum in the two cases is the same.

In fact, the change in momentum is given by:

\Delta p = m(v-u)

where:

m is the mass of the student

u is the initial velocity

v is the final velocity

In both cases, we have:

m = 75 kg

u = 8 m/s

v = 0 (they both comes to rest)

Therefore, the change in momentum is

\Delta p = (75)(0-8)=-600 kg m/s

3)

The impulse in the two cases is the same.

In fact, impulse is defined as the product of force applied, F, and duration of the collision, \Delta t:

J=F \Delta t

However, the force can be rewritten as product of mass (m) and acceleration (a), according to Newton's second law:

F=ma

So the impulse is

J=ma\Delta t

The acceleration can be rewritten as rate of change of velocity:

a=\frac{\Delta v}{\Delta t}

So the impulse becomes

J=m\frac{\Delta v}{\Delta t}\Delta t = m\Delta v

So, the impulse is equal to the change in momentum: and since in the two cases the change in momentum is the same, the impulse is the same as well.

4)

The force in the collision is related to the impulse by

J=F\Delta t

where

J is the impulse

F is the force

\Delta t is the duration of the collision

The equation can be rewritten as

F=\frac{J}{\Delta t}

In the two situations described in the problem (A and B), we already said that the impulse is the same (because the change in momentum is the same). However, in case A (padded wall) the time \Delta t is longer, while in case B (unpadded wall) the time \Delta t is shorter: since the force F is inversely proportional to the duration of the collision, this means that in case B the student will experience a greatest force compared to case A.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

3 0
3 years ago
Measuring Current as a Function of Voltage with a 20 Q Resistor
ki77a [65]

Answer:

<u>Resistance at 25 V</u>

Explanation:

(10)

(A)

10

20

100

200

Determining Current in a Parallel Circuit

Observed

Resistor Set

(0)

Total

Resistance

Calculated

Current

(A)

Current

(A)

(10)

20, 20, 20

20, 20, 200

<h3>Voltage needed to raise current to 3.75 A (20, 20, 200 resistor set):</h3>

Calculated

Observed:

Calculating Power of Circuit Components

Current through Each Bulb

(A)

Table B

Table C

Table D

Observed Total Current

(A)

Current Experimental

(A)

Observed Current

through Each Resistor

(A)

Power Usage per Bulb

(

4 0
2 years ago
At time t=0 a grinding wheel has an angular velocity of 26.0 rad/s. It has a constant angular acceleration of 25.0 rad/s^2 until
Zolol [24]

Angle turned by the wheel is given by the kinematics as

\theta = \omega t + \frac{1}{2}\alpha t^2

now here we know that

\omega = 26 rad/s

\alpha = 25 rad/s^2

t = 2.50 seconds

\theta = 26(2.50) + \frac{1}{2}(25)(2.50)^2

\theta = 143.1 rad

So here total angle that the wheel turn is given as

\theta = 143.1 + 440 = 583.1 rad

Speed of the wheel after 2.5 s

\omega = \omega_0 + \alpha t

\omega = 26 + (25)(2.5)

\omega = 88.5 rad/s

now angular deceleration is given as

\alpha_1 = \frac{\omega^2 - \omega_0^2}{2\theta}

\alpha_1 = \frac{0 - 88.5^2}{2(440)}

\alpha_1 = -8.9 rad/s^2

time taken to stop

t = \frac{\omega - \omega_0}{\alpha}

t = \frac{0 - 88.5}{-8.9} = 9.94 s

now total time is given as

T = 2.50 + 9.94 = 12.44 s

5 0
3 years ago
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How can cooler object can have more thermal energy than a warmer object?
Vladimir [108]
Temperature is only a measure of the average heat. It doesn't measure the quantity of heat. Even if a small cup of tea is really hot, it's so small. An iceberg is huge, and although cooler, will have much more heat, even if it's temperature is low
7 0
3 years ago
A wave travels through the air. The particles of the wave move at right angles to the motion of the energy of the wave.
maria [59]
Transverse Waves will be your answer I just saw the answer
6 0
3 years ago
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