Answer: 3.49 s
Explanation:
We can solve this problem with the following equation of motion:
(1)
Where:
is the final height of the ball
is the initial height of the ball
is the initial velocity (the ball was dropped)
is the acceleratio due gravity
is the time
Isolating
:
(2)
(3)
Finally we find the time the ball is in the air:
(4)
Answer:
a) E = 2.00 10³ J
, b) I = 6.66 10⁻⁶ N s
, c) F = 1.66 10⁻⁶ N
Explanation:
a) The intensity is defined as the power per unit area
I = P / A
P = I A
Power is energy for time
P = E / t
We replace
E / t = I A
E = I A t
E = 1.0 10³ 2.0 1.00
E = 2.00 10³ J
b) The moment is
p = U / c
In the case of a reflection the speed is reversed, so the moment
Δp = 2 U / c
I = Δp
I = 2 U / c
I = 2.00 10³/3 10⁸
I = 6.66 10⁻⁶ N s
c) The defined impulse is
I = F t
F = I / t
For a time of 1 s
F = 6.66 10⁻⁶ / 1
F = 1.66 10⁻⁶ N
d) Suppose n small mass mirror m = 10 10⁻³ kg, we write Newton's second law
F = ma
a = F / m
a = 1.66 10⁻⁶ / 10 10⁻³
a = 1.66 10⁻⁴ m / s
We see that the acceleration is very small and attended to increase the mass of the mirror will be less and less, so the assumption of no twisting of the mirror is very reasonable
Fundamental States,
Non-classical States.
Solid,
Liquid,
Gas and
Plasma.
The simplest arrangement of a reflex arc consists of the receptor, an interneuron (or adjustor), and an effector; together, these units form a functional group. Sensory cells carry input from the receptor (afferent impulses) to a central interneuron, which makes contact with a motor neuron.