Question

A blacksmith heats a 35 g lump of iron from room temperature until it glows (2425 degrees C) to work it. If the specific heat of iron is 0.450 j/g degrees C, how much thermal energy has it gained?

Answer 1

Answer:

37.9 kJ

Explanation:

We can calculate the thermal energy gained by the iron using the formula:

$Q=m C_s \Delta T$

where

m = 35 g is the mass of the iron

Cs = 0.450 j/g is the iron's specific heat capacity

$\Delta T= 2425 C - 20 C = 2405 C$ is the change in temperature of the iron (assuming that the room's temperature is 20 C degrees)

Substituting numbers into the formula, we find

$Q=(35 g)(0.450 J/g)(2405 C)=3.79\cdot 10^4 J=37.9 kJ$