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dolphi86 [110]
3 years ago
14

A wind turbine is initially spinning at a constant angular speed. As the wind's strength gradually increases, the turbine experi

ences a constant angular acceleration of . After making 2870 revolutions, its angular speed is 133 rad/s. (a) What is the initial angular velocity of the turbine? (b) How much time elapses while the turbine is speeding up?
Physics
1 answer:
Greeley [361]3 years ago
7 0

:Answer:

a. the initial angular velocity = 166.5rad/s

b. t= 135.7seconds

Explanation:

a. v = rw

angular velocity for 2870 rev, w = (2πN)/60 =2*3.142*2870rev)/60 =300.5rad/sec

w₁-w₂ = 300.5 - 133= 166.5rad/s

the initial angular velocity = 166.5rad/s

acceleration = change in velocity / time

b. 1 revolution = 2π

1 rad = 0.159rev

? = 2870 rev

=2870*1)/0.159 = 18050.3rad

the final angular speed = rev/time = rad/time

133 rad/s = 18050.3/t

133t = 18050.3

t= 135.7seconds

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Answer:

(a) The ratio of turns in the primary and secondary coils of her transformer is 1.833

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(c) To increase the output voltage, you can either increase the number of turns in the secondary coil (step-up) or increase the input current. Therefore, the Chinese person has to increase the input current of the transformer to achieve an increased output voltage that can power her 220 V appliances.

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Given;

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\frac{I_p}{I_s} = \frac{V_s}{V_p} \\\\\frac{I_p}{I_s} = \frac{120}{220} \\\\\frac{I_p}{I_s} = 0.55

(c) To increase the output voltage, you can either increase the number of turns in the secondary coil (step-up) or increase the input current. Therefore, the Chinese person has to increase the input current of the transformer to achieve an increased output voltage that can power her 220 V appliances.

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