Answer:
a) 1.92 m/s2
b) 11.64 rad/s2
c) 14.715 N
d) 2.43 Nm
Explanation:
a) Using the following equation of motion we can solve for the linear acceleration a:
where h = 6m is the vertical falling distance, and t = 2.5s is the time of falling
b) The angular acceleration of the rotating pulley can be calculated using its radius r = 0.165 m
c) As the tension of the cord is caused by the gravity acting on the falling bucket. Let g = 9.81m/s2, the weight of the bucket and tension of the cord would be
F = W = mg = 1.5*9.81 = 14.715 N
d) The torque generated by the tension would be the product of the tension itself and the distance to the pivot point, aka center of the pulley
T =Fr = 14.715 * 0.165 = 2.43 Nm