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julia-pushkina [17]
3 years ago
13

What is the molar mass of a gas if 1.30g of the gas has a volume of 245mL at STP? ...?

Physics
1 answer:
padilas [110]3 years ago
5 0
First, we assume this as an ideal gas so we use the equation PV=nRT. Then, we use the conditions at STP that would be 1 atm and 273.15 K. We calculate as follows:

PV= nRT
PV= mRT/MM

1 atm (.245 L) =1.30(0.08206)(273.15) / MM
MM = 118.94 g/mol <--- ANSWER
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Tasya [4]

There are 3 forces acting on the stoplight:

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• two tension forces <em>T</em>₁ and <em>T</em>₂ with equal magnitude <em>T</em>₁ = <em>T</em>₂ = <em>T</em> = 1000 N, both making an angle of <em>θ</em> with the horizontal, but one points left and the other points right

The stoplight is in equilibrium, so by Newton's second law, the net vertical force acting on it is 0, such that

∑ <em>F</em> = <em>T</em>₁ sin(<em>θ</em>) + <em>T</em>₂ sin(180° - <em>θ</em>) - <em>W</em> = 0

We have sin(180° - <em>θ</em>) = sin(<em>θ</em>) for all <em>θ</em>, so the above reduces to

2<em>T</em> sin(<em>θ</em>) = <em>W</em>

2 (1000 N) sin(<em>θ</em>) = 100 N

sin(<em>θ</em>) = 0.05

<em>θ</em> ≈ 2.87°

If <em>y</em> is the vertical distance between the stoplight and the ground, then

tan(<em>θ</em>) = (15 m - <em>y</em>) / (100 m)

Solve for <em>y</em> :

tan(2.87°) = (15 m - <em>y</em>) / (100 m)

<em>y</em> = 15 m - (100 m) tan(2.87°)

<em>y</em> ≈ 9.99 m

3 0
3 years ago
An object is placed between two plain mirrors which make angle 45 degree with each other. Distance between all adjacent images a
marysya [2.9K]
I have a formula here that might just help you solve the problem on your own:

The number of images depends on the angle between the two mirrors. The number of images formed in two plane mirrors inclined at an angle A to each other is given by the formula:

Number of images = 360<span>/A - 1.
</span>
I hope my guide has come to your help. God bless and have a nice day ahead!
3 0
3 years ago
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Answer:

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a disk of a radius 50 cm rotates at a constant rate of 100 rpm. what distance in meters will a point on the outside rim travel d
vlabodo [156]

Answer: 50π m ≈ 157 m

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