Which ion is formed when an atom of fluorine (F) gains one electron?

Chemistry

2 answers:

dybincka [34]3 years ago

8 0

The answer is F-1since it is gaining therefore you can take this as electron affinity.

Viktor [21]3 years ago

6 0

Answer: Option (a) is the correct answer.

Explanation:

When an atom or element gains an electron then the atom acquires a negative charge whereas when an atom or element loses an electron then it acquires a positive charge.

for example, atomic number of fluorine is 9 and when it gains one electron then fluorine atom acquires a negative charge. Hence, neutral atom of fluorine changes into $F^{-1}$ ion.

Thus, we can conclude that $F^{-1}$ ion is formed when an atom of fluorine (F) gains one electron.

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Explanation:

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When the equation Sn + HNO₃ → SnO₂ + NO₂ + H₂O is balanced in acidic solution, what is the smallest whole-number coefficient for

balu736 [363]

Answer:

Explanation:

Hello,

In this case, for the given reaction we first assign the oxidation state for each species:

$Sn^0 + H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 + N^{4+}O^{2-}_2 + H^+_2O^-$

Whereas the half reactions are:

$Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-\\\\H^++H^+N^{5+}O^{-2}_3 +1e^-\rightarrow N^{4+}O^{2-}_2+H_2O$

Next, we exchange the transferred electrons:

$1\times(Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-)\\\\4\times (H^++H^+N^{5+}O^{-2}_3 +1e^-\rightarrow N^{4+}O^{2-}_2+H_2O)\\\\\\Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-\\\\4H^++4H^+N^{5+}O^{-2}_3 +4e^-\rightarrow 4N^{4+}O^{2-}_2+4H_2O$