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slamgirl [31]
2 years ago
10

16.45 centimeter = decameter

Chemistry
2 answers:
aev [14]2 years ago
7 0
<h2>Answer:</h2><h2>0.01641 decameter</h2>

A Brainliest please

Good luck .

Mamont248 [21]2 years ago
5 0

Answer: 0.01645

Explanation:to long tosovles.

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Which property of potential energy distinguishes it from kinetic energy
satela [25.4K]
The property of potential energy that distinguishes it from kinetic energy are Shape and position 
8 0
3 years ago
Calcium chloride has a melting point of 772°C, and water has a boiling point of 100°C. Which statement is true for calcium chlor
KonstantinChe [14]
C) Calcium chloride has stronger inter molecular forces than water.
4 0
3 years ago
Read 2 more answers
What is the expected value for the heat of sublimation of acetic acid if its heat of fusion is 10.8 kJ/mol and its heat of vapor
Dennis_Churaev [7]

Answer:

35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.

Explanation:

CH_3COOH(l)\rightarrow CH_3COOH(g)..[1]

Heat of vaporization of acetic acid = H^o_{vap}=24.3 kJ/mol

CH_3COOH(s)\rightarrow CH_3COOH(l)..[2]

Heat of fusion of acetic acid = H^o_{fus}=10.8 kJ/mol

Heat of sublimation of acetic acid = H^o_{sub}=?

CH_3COOH(s)\rightarrow CH_3COOH(g)..[3]

[1] + [2] = [3] (Hess's law)

H^o_{sub}=H^o_{vap}+H^o_{fus}

=24.3 kJ/mol+10.8 kJ/mol=35.1 kJ/mol

35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.

5 0
3 years ago
If 2.60 g of NaBr are dissolved in enough water to make 160. mL of solution, what is the molar concentration of
navik [9.2K]

This problem has two parts; the first one asking for the concentration of NaBr given both its mass and volume and the second one asking for its volume given both mass and concentration. The answers turn out to be 0.158 M and 211 mL.

<h3>Molarity</h3>

In chemistry, the use of units of concentration depends on both the substances to analyze and their amounts. In such a way, for molarity, one needs the following relationship between the moles of solute and volume of solution:

M=\frac{n}{V}

Thus, for the first part of the problem we first calculate the moles in 2.60 g of NaBr via its molar mass:

2.60g*\frac{1mol}{102.89g} =0.0253mol

Next, we convert the 160. mL to L by dividing by 1000 in order to obtain 0.160 L to subsequently calculate the molarity:

M=\frac{0.0253mol}{0.160L}=0.158M

Next, since the moles remain the same and for the second part we are asked for the volume given the concentration, one can solve for the volume so as to obtain:

V=\frac{n}{M} =\frac{0.158M}{0.120mol/L}\\ \\V=0.211L

That in milliliters turns out to be:

V=0.211L*\frac{1000mL}{1L}=211mL

Learn more about molarity: brainly.com/question/10053901

6 0
1 year ago
Object a has a mass of 12 G and a volume of 8 cm3 object be has a mass of 20 G and a volume of 8 cm3 which object has a greater
solniwko [45]

Answer:

Option C = object B by 1 gram per cubic cm.

Explanation:

Given data:

Mass of object A = 12 g

Volume of object A = 8 cm³

Mass of object B = 20 g

Volume of object B = 8 cm³

Densities = ?

Solution:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Density of object A:

d = m/v

d = 12 g/ 8 cm³

d = 1.5 g/cm³

Density of object B:

d = m/v

d = 20 g/ 8 cm³

d = 2.5 g/cm³

object b has high density.

5 0
3 years ago
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