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4 years ago

10

HELP ASAP!!! Some bands hate playing in school gyms because sound waves easily reflect off the walls and floor. What could you d

o to the gym walls to improve the sound quality?

1 answer:

Virty [35]4 years ago

6 0

Answer:

I would recommend placing something on the ground or on the walls of your gym to damped the echos.

Explanation:

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A long solenoid, of radius a, is driven by an alternating current, so that the field inside is sinusoidal: B(t) B cos(ot)ż. A ci

Scrat [10]

Answer:

The current induced in the loop is $\dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t)$ .

Explanation:

Given that,

Magnetic field $B(t)=B\cos(\omega t)\ z$

Radius $r =\dfrac{a}{2}$

Resistance =R

We need to calculate the area of the loop

Using formula of area

$A = \pi r^2$

Put the value of r in to the formula

$A =\pi\times(\dfrac{a}{2})^2$

$A=\dfrac{\pi a^2}{4}$

We need to calculate the flux

Using formula of flux

$\phi=BA$

$\phi=B\cos(\omega t)\dfrac{\pi a^2}{2}$

We need to calculate the emf

Using formula of emf

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{-\pi a^2B}{4}(-\omega\sin\omega t)$

$\epsilon=\dfrac{\pi a^2B\omega\sin(\omega t)}{4}$

We need to calculate the current

Using formula of current

$I(t)=\dfrac{\epsilon}{R}$

$I(t)=\dfrac{\dfrac{\pi a^2B\omega\sin(\omega t)}{4}}{R}$

$I(t)=\dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t)$

Hence, The current induced in the loop is $\dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t)$ .

4 0

3 years ago

A car travelling at 20 m/s due north along the highway makes a right turn on to a side road that heads due east. It takes 50 s f

Marrrta [24]

Answer: initial velocity: 20 m/s

time taken to complete the turn: 50s

final velocity: 15 m/s

average acceleration= final velocity-initial velocity/time taken - 0s( 0 is taken here as there was no initial time)

= 15-20/50-0

= -5/50= -0.1 ms^2

3 0

3 years ago

Help please physics !!

malfutka [58]

Answer:

Option A. 1 bar = 1 atm

Explanation:

Pressure has various units of measurement. Each unit of measurement can be converted to other units of measurement. For example:

1 atm = 1 bar

1 atm = 760 mmHg

1 atm = 760 torr

1 atm = 1×10⁵ N/m²

1 atm = 1×10⁵ Pa

With the above conversion scale we can convert from one unit to the other.

Considering the question given above, it is evident from the coversion scale illustrated above that only option A is correct.

Thus,

1 bar = 1 atm

5 0

3 years ago

A 32.0 kg wheel, essentially a thin hoop with radius 1.20 m, is rotating at 280 rev/min. It must be brought to a stop in 15.0 s.

elena-14-01-66 [18.8K]

Answer:

A) Must be done 19806.62 joules of work.

B) The average power is 1320.44 Watts.

Explanation:

A) First, we're going to use the work-energy theorem that states total work ( $W$ ) done on an object is equal to the change in its kinetic energy ( $\Delta K$ ):

$W=\Delta K = K_{f}-K_{i}$ (1)

So, all we must do is to find the change on kinetic energy. Because we're working with rotational body, we should use the equation $K=\frac{I\omega^{2}}{2}$ for the kinetic energy so:

$\Delta K=\frac{I(\omega_{f})^{2}}{2}-\frac{I(\omega_{i})^{2}}{2}$ (2)

with $\omega_{i}$ the initial angular velocity, $\omega_{f}$ the final angular velocity (is zero because the wheel stops) and I the moment of inertia that for a thin hoop is $I=MR^{2}$ , using those on (2)

$\Delta K=0-\frac{MR^{2}(\omega_{i})^{2}}{2}$ (3)

By (3) on (1):

$W= \frac{MR^{2}(\omega_{i})^{2}}{2} = \frac{(32.0)(1.2)^{2}(29.32)^{2}}{2}$

$W=19806.62\,J$

B) Average power is work done divided by the time interval:

$P=\frac{W}{\Delta t}=\frac{19806.62}{15.0}$

$P=1320.44\,W$

NOTE: We use the relation $1rpm*\frac{2\pi}{60s}=\frac{rad}{s}$ to convert 280 rev/min(rpm) to 29.32 rad/s

4 0

4 years ago

Name the blood vessels that carry blood from the upper and lower parts of your body

aev [14]

Pulmonary Arteries: Blood vessels that carry deoxygenated blood from the heart to the lungs. Superior Vena Cava: A large vein that delivers deoxygenated blood from the upper body into the heart. Hope this helps

3 0

4 years ago

Read 2 more answers