Answer:
given -
initial velocity = 4.09 m/s
acceleration = 1.01 m/s²
distance = 23.4 m
time = ?
using second formula of motion,
s = ut + 1/2 at².
where, s = distance
u = initial velocity
t = time
a = acceleration
23.4 = 4.09(t) + 1/2(1.01)(t) ²
23.4 = 4.09t + 2.02t²
2.02t² + 4.09t - 23.4 = 0
solving the equation by using quadratic formula
Use the standard form, ax² + bx + c = 0 , to find the coefficients of our equation, :
a = 2.02
b = 4.09
c = -23.4
we get t=2.539 or t= -4.563
time cannot be negative so
t= 2.539 sec = 2.6 Sec is the answer
The formulas are-
a=f/m
f=ma
m=f/a
Use this numbers that you are given and plug them into the formule for net force
Net force= m*a (mass times acceleration)
Therefore the net force is equal to (5.5 kg)*(4.2 m/s^2)= 23.1 N
Answer: Net force= 23.1 N
Hello There!
Answer is provided in the image attached.
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Answer:
K so I worked on this not so long ago the answer I put was : It really depends on how to track is if it is a flat one then the force stays the same but if the track is whre you are going down then your velocity goes up as well as the speed increases with but if your going up a track then your speed decreases.
