It is based on the water underground
D=m/v ⇒ m=d*v
d=density
m=mass
v=volume
d(ether)=0.71 gr/cm³=0.71 gr/ ml
v=130 ml
m=d*v
m=0.71 gr/ml*(130 ml)=92.3 g
Solution: m=92.3 g
Answer:
ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.
Explanation:
