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Sunny_sXe [5.5K]
4 years ago
10

Write the chemical equation for the formation of HI from the single, isolated H and I atoms.

Chemistry
1 answer:
mart [117]4 years ago
7 0

Answer:

H2 + I2 → 2 HI.

Explanation:

Hydrogen iodide is a diatomic gas which can be readily formed from the direct combination of the elements involved which is hydrogen and iodine. Both elements can be combined by irradiating the mixture with an electromagnetic radiation that has a wavelength which is equal to that needed to break the iodine molecule bond between the two iodine atoms

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PLEASE HELP!! PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP’
ahrayia [7]

Answer:

B is the answer because it doesn't matches the num of valence electrons

8 0
3 years ago
Read 2 more answers
If carbon lost one proton, what atom would be formed
Rudiy27

Answer:

boron

Explanation:

boron has 5 protons and carbon has 6, so if carbon lost a proton, it would become boron since each element has a unique number of protons.

5 0
3 years ago
Balance the chemical equation.Au plus HC l plus HNO 3 right arrow AuC l Subscript 3 Baseline plus NO plus Upper H 2 Upper OAu+HC
tino4ka555 [31]

Answer:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

Explanation:

Chemical Equations are representations of chemical reactions in terms of the symbols and formulae of the elements and compounds involved. A chemical equation usually have the reactant at the left hand side while the product is on the right hand side.

A chemical Equation is of little or no value if is not in balanced equation. When an equation is balanced , the total number of atoms of any element on the left-hand side of it must be equal to the total number of atoms of that element on the right hand side.

in the given question; we are given a word problem of chemical symbol to  compute and also to balance the chemical equation.

From below; the chemical equation can be written as:

Au+ HCl + HNO_3 \to AuCl_3+NO+2H_2O

From the above  equation we will notice  that  it is not truly balanced ; so th balanced equation can be written as:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

5 0
3 years ago
What is the density of a 6 g of pure copper with a volume of 12 mL?
Sati [7]

Answer:

The density of copper is 0.5 g/mL

Explanation:

Given data:

Mass of copper = 6 g

Volume of copper = 12 mL

Density of copper = ?

Solution:

Formula:

d = m/v

d = density

m = mass

v = volume

d = 6 g/ 12 mL

d = 0.5 g/mL

Thus, the density of copper is 0.5 g/mL

5 0
3 years ago
F(x) = 2|x+2| - 8 I need help ​
Korolek [52]

Answer: |x+2|=xF2+4

Explanation: not sure if this is right im just guessing

8 0
3 years ago
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