Answer:
3.125 × 10¹³ Electrons
Explanation:
Data provided in the question:
Charge per unit length on rod = 0.00500 C/m
Length of the rod = 1 mm = 1 × 10⁻³ m
Therefore, the total charge on the rod
= Charge per unit length on rod × Length of the rod
= 0.00500 C/m × ( 1 × 10⁻³ m)
= 5 × 10⁻⁶ C
Thus,
Number of electrons removed
= total charge on the rod ÷ Charge of an electron
= 5 × 10⁻⁶ ÷ (1.6 × 10⁻¹⁹)
= 3.125 × 10¹³ Electrons
Molecules in solids are packed a lot closer together than molecules in liquids and gases, so there is far less space between solid particles. Because of this, solid particles cannot move around quickly and freely like liquids and gases, instead they only vibrate so are fairly 'locked' into the same place, so solids have fixed volume and space.
So here we are given that the the velocity of the proton ( V ) is 2.0 × 
meters / second, with a magnetic field of strength 5.5 × 
tesla. If they each form a right angle, they are hence perpendicular to one another, such that ....
F = q( V × B ),
F = q v B( sin ∅ ),
F = q v B( sin( 90 ) )
.... they form the following formula. Let's go through each of the variables in our formula here -
{ F = Magnetic Force ( which has to be calculated ), q = charge of proton (has charge of 1.602 × 
coulombs ), B = magnetic field }
All we have to do now is plug and chug,
F = ( 1.602 × )( 2.0 × )( 5.5 × ) = ( About ) 1.8 × 
Newtons
Hi!
I think the oxidation state of all the atoms should change. :)
Hope this helps
Answer: yo sorry this a hard one
Explanation:
bro
