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3 years ago

At which electrode does oxidation occur in a

Chemistry

2 answers:

lisabon 2012 [21]3 years ago

7 0

Answer: Option (3) is the correct answer.

Explanation:

Both voltaic cell and electrochemical cells are used to produce electrical energy with the help of chemical reactions.

These cells also contain a salt bridge which helps in the neutrality of ions.

Therefore, in both the cells oxidation reaction occurs at anode and reduction reaction occurs at cathode.

Therefore, we can conclude that at the anode in both a voltaic cell and an

electrolytic cell oxidation occurs.

Charra [1.4K]3 years ago

6 0

(3) the anode in both a voltaic cell and an electrolytic cell is your answer.

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What are the principal alloy elements of an AISI 4340 steel? How much carbon does it have? Is it hardenable? By what techniques?

amid [387]

Answer:

The principal elements are Iron, Nickel, Chromium

It has 0.37% to 0.43% Carbon

It is hardenable.

It can be hardened by cold working, annealing, quenching.

Explanation:

The chemical composition of AISI 4340 Steel are as follows:

Iron --- 95% to 96%

Nickel --- 1.6% to 2.0%

Chromium --- 0.7% to 0.9%

Manganese --- 0.6% to 0.8%

Carbon --- 0.37% to 0.43%

Molybdenum --- 0.2% to 0.3%

Silicon --- 0.15% to 0.30%

Sulfur --- 0.040%

Phosphorous --- 0.0350%

So, the principal alloy elements from this composition are Iron, Nickel and Chromium

The carbon content in this alloy is 0.37% to 0.43%

Yes, it can be hardened.

It can be Hardened by Cold Working, Annealing or Quenching.

3 0

2 years ago

Whether or not the process is observed in nature, which of the following could account for the transformation of gallium-67 to z

Sonja [21]

Answer:

Option a: positron emission.

Explanation:

In the transformation we have:

⁶⁷Ga → ⁶⁷Zn

The reaction is:

$^{67}_{Z}X \rightarrow ^{67}_{Z -1}Y$

For Ga to become Zn, the atom nucleus has to lose a proton, so in the given options, the reaction that involves the transformation of a proton is the option a, positron emission.

In a positron emission, a proton becomes into a neutron and a positron:

$^{A}_{Z}X \rightarrow ^{A}_{Z-1}Y + ^{0}_{+1}e$

Therefore, the correct answer is option a: positron emission.

I hope it helps you!

7 0

3 years ago

What is the value of all conversion factors that are used in dimensional analysis

IRISSAK [1]

All the conversions have a net value of 1

4 0

3 years ago

Read 2 more answers

Diffusion of nonpolar molecules would not be affected by

wariber [46]

+molecule size +steepness of the concentration gradient +temperature + steepness of the electric gradient +steepness

7 0

3 years ago

The naturally occurring radioactive decay series that begins with 23592U stops with formation of the stable 20782Pb nucleus. The

dsp73

Answer: There are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.

In radioactive decay the sum of atomic number or mass number of reactants must be equal to the sum of atomic number or mass number of products .

$_{92}^{235}\textrm{U}\rightarrow _{82}^{207}\textrm{Pb}+X_2^4\alpha+Y_{-1}^0e$

Thus for mass number : 235 = 207+4X

4X= 28

X = 7

Thus for atomic number : 92 = 82+2X-Y

2X- Y = 10

2(7) - Y= 10

14-10 = Y

Y= 4

$_{92}^{235}\textrm{U}\rightarrow _{82}^{207}\textrm{Pb}+7_2^4\alpha+4_{-1}^0e$

Thus there are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series

3 0

3 years ago