All categories

2 years ago

Action and reaction forces will cancel because they are pushing on the same object toward each other. True or False

Physics

2 answers:

sweet-ann [11.9K]2 years ago

5 0

Answer:

False

Explanation:

Newton's third law states that for every action there is an equal and opposite reaction. The action-reaction pair act on different bodies. Thus, they do not cancel each other.

For example, in order to walk, we push the floor backwards. This is action force which the foot applies to the floor. The floor pushes the foot forward. This is the reaction force. The amount of force is equal but the direction is opposite. Also, the bodies on which action force and reaction force are acting are different.

Hence, the given statement is false.

vampirchik [111]2 years ago

4 0

Sometimes. If the forces are equal, they will cancel out and the net force will be zero. But if the forces are not equal, the object will move away from the stronger force because there is still a net force.

You might be interested in

Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.00×104 Pa . Assum

cestrela7 [59]

Answer:

$T_{2}=278.80 K$

Explanation:

Let's use the equation that relate the temperatures and volumes of an adiabatic process in a ideal gas.

$(\frac{V_{1}}{V_{2}})^{\gamma -1} = \frac{T_{2}}{T_{1}}$ .

Now, let's use the ideal gas equation to the initial and the final state:

$\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}}$

Let's recall that the term nR is a constant. That is why we can match these equations.

We can find a relation between the volumes of the initial and the final state.

$\frac{V_{1}}{V_{2}}=\frac{T_{1}p_{2}}{T_{2}p_{1}}$

Combining this equation with the first equation we have:

$(\frac{T_{1}p_{2}}{T_{2}p_{1}})^{\gamma -1} = \frac{T_{2}}{T_{1}}$

$(\frac{p_{2}}{p_{1}})^{\gamma -1} = \frac{T_{2}^{\gamma}}{T_{1}^{\gamma}}$

Now, we just need to solve this equation for T₂.

$T_{1}\cdot (\frac{p_{2}}{p_{1}})^{\frac{\gamma - 1}{\gamma}} = T_{2}$

Let's assume the initial temperature and pressure as 25 °C = 298 K and 1 atm = 1.01 * 10⁵ Pa, in a normal conditions.

Here,

$p_{2}=8.00\cdot 10^{4} Pa \\p_{1}=1.01\cdot 10^{5} Pa\\ T_{1}=298 K\\ \gamma=1.40$

Finally, T2 will be:

$T_{2}=278.80 K$

6 0

3 years ago

The force of gravity on Mercury is less than the Earth because:

Vinvika [58]

Mercury has less mass than earth. So the answer is B

7 0

2 years ago

Read 2 more answers

How many number of musicians constitute a big band?

nikitadnepr [17]

Big band is music group (a group of people who perform instrumental and/or vocal music ) playing jazz or jazz-influenced popular music and which was popular during the Swing Era from the mid-1930s until the late 1940s. These big bands contained saxophones, trumpets, trombone and other instruments and typically consisted of approximately 12 to 25 musicians.

6 0

3 years ago

Test questions!!!!!!!!

Pani-rosa [81]

Answer:

B. surface wave

8 0

2 years ago

5b) how fast is the car going after 6 seconds?

jeka94

Answer:

No imageeeeeeeeeeeeeeeeeeeeee