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nadya68 [22]
4 years ago
7

What is the maximum kinetic energy of an ejected electron if silver metal is irradiated with 224 nm light? The

Chemistry
1 answer:
Genrish500 [490]4 years ago
3 0

Answer:The maximum kinetic energy KEe of ejected electrons (photoelectrons) is given by KEe=hf−BE KE e = h f − BE , where hf is the photon energy and BE is the binding energy (or work function) of the electron to the particular material.

Explanation:

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Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation C
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Answer:

70.3824 grams of carbondioxide is produced.

Explanation:

C_6H_{12}O_6(aq)+6O_2(g)⟶6CO_2(g)+6H_2O(l)

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According to reaction 1 mole of glucose reacts with 6 mole of oxygen gas.

Then 0.2666 mol of gluocse will reactwith :

\frac{6}{1}\times 0.2666 mol =1.5996 mol of oxygen

Mass of 1.5996 moles of oxygen gas:

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51.1872 grams of oxygen are required to convert 48.0 grams of glucose to CO_2 and H_2O.

According to reaction, 1 mol, of glucose gives 6 moles of carbon dioxide.

Then 0.2666 moles of glucose will give:

\frac{6}{1}\times 0.2666 mol =1.5996 mol of carbon dioxide

Mass of 1.5996 moles of carbon dioxide gas:

1.5996 mol\times 44 g/mol = 70.3824 g

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