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Karolina [17]
2 years ago
13

The net force (unbalanced force) applied on an object is the product of_________and___________​

Physics
1 answer:
RSB [31]2 years ago
5 0

Answer:

of its <u>mass</u> and its <u>acceleration</u>

<u>Explanation:</u>

based on Newton's second law of motion

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First, convert the ft to standard units of meters.
1 foot = <span>0.3048 meters
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Then, we will use the laws of motion to calculate the time:
x = 0.5 at^2
where:
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a is the gravity (9.8 m/sec^2)
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t^2 = 147.5232 / (0.5 x 9.8)
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When an object absorbs light energy, it reflects
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4 0
3 years ago
A hot-air balloon and its basket are accelerating upward at 0.265 m/s2, propelled by a net upward force of 688 N. A rope of negl
Sergeu [11.5K]

Question:<em> </em><em>Find, separately, them mass of the balloon and the basket (incidentally, most of the balloon's mass is air)</em>

Answer:

The mass of the balloon is 2295 kg, and the mass of the basket is 301 kg.

Explanation:

Let us call the mass of the balloon m_1 and the mass of the basket m_2, then according to newton's second law:

(1). \:F = (m_1+m_2)a,

where a =0.265m/s^2 is the upward acceleration, and F = 688N is the net propelling force (counts the gravitational force).

Also, the tension T in the rope is 79.8 N more than the basket's weight; therefore,

(2). \:T = m_2g+79.8

and this tension must equal

T -m_2g =m_2a

(3). \:T = m_2g +m_2a

Combining equations (2) and (3) we get:

m_2a = 79.8

since a =0.265m/s^2, we have

\boxed{m_2 = 301.13kg}

Putting this into equation (1) and substituting the numerical values of F and a, we get:

688N = (m_1+301.13kg)(0.265m/s^2)

\boxed{m_1 = 2295 kg}

Thus, the mass of the balloon and the basket is  2295 kg and 301 kg respectively.

8 0
3 years ago
An oil film with refractive index 1.48 and thickness 290 nm is floating on water and illuminated with white light at normal inci
VikaD [51]

Answer:

572.3 nm

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n_{oil} = refractive index of the oil film = 1.48

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m = order

Using the equation

2 n_{oil} t_{oil} = (m + 0.5) \lambda

For m = 0

2 (1.48) (290) = (0 + 0.5) \lambda

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For m = 1

2 (1.48) (290) = (1 + 0.5) \lambda

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For m = 2

2 (1.48) (290) = (2 + 0.5) \lambda

\lambda = 343.4 nm

Hence the dominant color wavelength is 572.3 nm

8 0
4 years ago
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