Answer: No, because the atomic number shown in the symbol (Z = 15) is not the atomic number of oxygen (Z = 8)
Explanation:
When we have an atom, the number in the top left is the mass number A, is equal to the sum between the number of neutrons and protons in the atom.
In this case, between protons and neutrons, we have 32.
The number at the bottom left is the atomic number Z, which is equal to the number of protons in the atom.
Particularly, this number is different for every element. For example, for the oxygen we would have Z = 8, this means that the oxygen has 8 protons.
In the image, we can see Z = 15, then the atom has 15 protons, this means that it can not be oxygen (Z = 15 is for phosphorus, then this atom would be phosphorrs). Then the symbol can not be used, because that is not oxygen.
Answer:
yes
Explanation:
because it is a diverging mirror
Hi there!
Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:
Wsinθ = downward acceleration along incline due to gravity (N)
Fκ = kinetic friction force along incline (N)
A = applied force (N)
The acceleration due to gravity and friction force act in the same direction, so:
Wsinθ + Fκ = A
Solve for sinθ using right triangle trigonometry:
sinθ = O/H = 3/6 = 0.5
Rearrange the equation for the force of kinetic friction and solve:
Fκ = A - 0.5W
Fκ = 30.4 - 20 = 10.4 N
Now, recall that:
Work = Force × displacement (W = F × d)
Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:
W = Fdcosθ
Angle between displacement and friction force is 180°.
cos(180) = -1
Work done by friction = -Fd = -10.4(6) = -62.4 J
Speed = (wavelength) x (frequency
Speed = (.020 m) x (5 / sec)
Speed = 0.1 m/s
At the beginning of a basketball game, a referee tosses the ball straight
up with a speed of 4.6 m/s. a player cannot touch the ball until after it reaches its maximum height and begins to fall down. what is the minimum time that a player must wait before touching the ball? s
-----------------------
kinemaic equation
v=u-at
0=4.6-9.81xt
t=4.6/9.81 ... about half a second
