Answer:
2.31 EHz
Explanation:
The formula relating the frequency (f) and wavelength (λ) is
fλ = c Divide both sides by λ
f = c/λ
c = 2.998 × 10⁸ m·s⁻¹
λ = 1.15 × 10⁻¹⁰ m Calculate f.
f = 2.998 × 10⁸/1.15 × 10⁻¹⁰
f = 2.61 × 10¹⁸ s⁻¹ = 2.61 EHz
Kinetic energy maybe or something
<span>Longshore drift is a geographical process that consists of the transportation of sediments (clay, silt, sand and shingle) along a coast at an angle to the shoreline, which is dependent on prevailing wind direction, swash and backwash. This process occurs in the littoral zone, and in or close to the surf zone.</span>
The reactant in a chemical process known as the limiting reactant controls how much product can be produced. When the limiting reactant is completely used up, the reaction will come to an end.
<h3>
Find the limiting reactant ?</h3>
- As a result of 1 mol Sb4O6 reacting with 6 mol H2SO4, only 0.1 mol Sb4O6 reacts with 0.6 mol H2SO4, leaving only 0.5 mol H2SO4. This indicates that H2SO4 is the limiting reactant and Sb4O6 is present in excess.
- According to your equation, which is balanced, 0.1 mol Sb4O6 should react with 0.6 mol H2SO4, yet there is only 0.5 mol H2SO4 on hand.
- Therefore, only.083 mol of Sb4O6 are reacted.
- The reactant that is present in the limiting amount—the limiting reactant—determines the extent to which a chemical reaction occurs.
- The trick is really quite easy! We employ an augmented matrix to hold the data derived from the balancing equation Sb4O6 + 6H2SO4 --> 2Sb2(SO4)3 + 6H2O.
- Although you are provided 0.5 mol of H2SO4, the reaction requires 0.6 mol. Therefore, the limiting reactant is H2SO4.
- Only 0.0833 mol of Sb4O6 is required, but you have 0.1 mol. Sb4O6 is therefore the extra reactant.
To learn more about limiting reactant refer to:
brainly.com/question/27986321
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Alkaline solutions are basic so answer is C basic
