Answer:
36 valence electrons
Explanation:
Given CBr₂COHNH₂ => Br₂C = C - O - H
|
H - N - H
#Valence e⁻s = 2Br + 2C + 3H + 1N + 1O = 2(7) + 2(4) + 3(1) + 1(5) + 1(6)
= 14 + 8 + 3 + 5 + 6 = 36 valence electrons
Addendum ...
#Bonded e⁻s = 2Br + 2C + 3H + 1N + 1O = 2(8) + 2(8) + 3(2) + 1(8) + 1(8)
= 16 + 16 + 6 + 8 + 8 = 54 bonded electrons
#Covalent Bonds = #Valence e⁻ - #Bonded e⁻ / 2 = (54 - 36) / 2 = 9 cov. bonds.
<span>Antimony(V) Chlorate
hope this helps!</span>
The two sublevels are s and p. These are the main group sublevels
The answer is False for sodium bromide it would be NaBr
