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hodyreva [135]
3 years ago
15

Please need help on this

Physics
1 answer:
kirill115 [55]3 years ago
8 0
The frequency cannot change, as it depends on the source. now, imagine light as a particle, when it's going through glass, which is a denser medium than air, is more tightly packed with particles than air is. think of it this way, will you walk faster in a crowd or on an empty street? going through the empty street (air) there are lesser objects to bump into so what do you think will happen to the speed now?
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Objects with masses of 165 kg and a 465 kg are separated by 0.340 m. (a) Find the net gravitational force exerted by these objec
Dmitrij [34]

Answer:

(a) F_{net} = 4.19 x 10^{-5} N, and its direction is towards m_{2}.

(b) It must be placed inside a hollow shell.

Explanation:

Let, m_{1} = 165 kg, m_{2} = 465 kg, m_{3} = 60 kg, and the distance between m_{1} and m_{2} is 0.340 m.

(a) Since m_{3} is placed midway between m_{1} and m_{2}, then its distance to both masses is 0.170 m.

From the Newton's law of universal gravitation,

F = \frac{Gm_{1}m_{2}  }{r^{2} }

Where all variables have their usual meaning.

Then,

a. F_{net} = F_{23} - F_{13}

F_{13} = \frac{6.67*10^{-11}*165*60 }{(0.17)^{2} }

     = 2.25 x 10^{-5} N

F_{23} = \frac{6.67*10^{-11}*465*60 }{(0.17)^{2} }

     = 6.44 x 10^{-5} N

∴ F_{net} =  = 6.44 x 10^{-5} - 2.25 x 10^{-5}

              = 4.19 x 10^{-5} N

The net force exerted by the two masses on the 60 kg object is 4.19 x 10^{-5}  N.

(ii) /F_{net}/ = /F_{23}/ - /F_{13}/

              = 6.44 x 10^{-5} - 2.25 x 10^{-5}

              = 4.19 x 10^{-5} N

(iii) The direction of the net force is to the right i.e towards m_{2}.

(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.

7 0
3 years ago
A body travels the first half of the total distance with velocity v and second half with v2 calculate avg velocity
LuckyWell [14K]

Answer:

v = 2 v₁ v₂ / (v₁ + v₂)

Explanation:

The body travels the first half of the distance with velocity v₁.  The time it takes is:

t₁ = (d/2) / v₁

t₁ = d / (2v₁)

Similarly, the body travels the second half with velocity v₂, so the time is:

t₂ = (d/2) / v₂

t₂ = d / (2v₂)

The average velocity is the total displacement over total time:

v = d / t

v = d / (t₁ + t₂)

v = d / (d / (2v₁) + d / (2v₂))

v = d / (d/2 (1/v₁ + 1/v₂))

v = 2 / (1/v₁ + 1/v₂)

v = 2 / ((v₁ + v₂) / (v₁ v₂))

v = 2 v₁ v₂ / (v₁ + v₂)

8 0
3 years ago
What is surface tension? How does surface tension result from intermolecular forces? How is it related to the strength of interm
Bond [772]

Answer:

Surface tension is the tendency of liquid surfaces to shrink into the minimum surface area possible.

Surface tension is caused by effects of intermolecular forces at liquid interface.

Surface tension increases as intermolecular forces increases.

Explanation:

  • Surface tension is the tendency of liquid surfaces to shrink into the minimum surface area possible. It can also be seen as the energy required to increase the surface of a liquid by a unit amount.
  • Surface tension is caused by the mediating effects of intermolecular forces at the liquid interfaces. Example in water, surface tension is caused by the mediating effect of the force between hydrogen and oxygen molecules. Liquids tends to reduce their surface area because of inward attarction of the liquid molecules.
  • Surface tension increases as intermolecular forces increases. Also, surface tension decreases as intermolecular forces decreases.

3 0
3 years ago
A 110 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.220 m/s. How much work must be d
Softa [21]

Answer:

the work that must be done to stop the hoop is 2.662 J

Explanation:

Given;

mass of the hoop, m = 110 kg

speed of the center mass, v = 0.22 m/s

The work that must be done to stop the hoop is equal to the change in the kinetic energy of the hoop;

W = ΔK.E

W = ¹/₂mv²

W = ¹/₂ x 110 x 0.22²

W = 2.662 J

Therefore, the work that must be done to stop the hoop is 2.662 J

6 0
3 years ago
If there is a negative sign in front of the Hooke's Law equation, what does the force, F, represent?
solong [7]

Answer:

C) The restoring force

Explanation:

Hooke's Law states that the restoring force acting on a spring is given by the equation:

F=-kx

where

k is the spring constant

x is the displacement of the spring from its equilibrium position

The negative sign in the equation tells the direction of the restoring force. In fact, this force tends to bring the spring back to its equilibrium position: so, the force is always in opposite direction to the displacement.

This means that when the spring is stretched to the right, the restoring force tends to bring it back to the left, to the equibrium position; if the spring is compressed to the left, the restoring force tends to bring it back to the right, to the equilibrium position.

So the correct option is

C) The restoring force

3 0
3 years ago
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